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3 years ago

Please help me answer this.

Mathematics

2 answers:

mihalych1998 [28]3 years ago

6 0

Answer: B. y=3x+7.5

Step-by-step explanation:

First, you find m by doing $\frac{y_2 - y_1}{x_2 - x_1} =m$ . You end up with $m=2$ . Then you plug it into $(y-y_0)=m(x-x_0)$ to find the b in $y=mx+b$ . When you do that, you get $b=7$ . So, you end up with the equation of the table as $y=2x+7$ and since it's a linear function, the slope (m) won't change. Now you compare this equation to the others given. The slope in answer A is too small and the y-intercepts in answers B and C are too small, so you are left with b as your only option.

Inga [223]3 years ago

4 0

Answer:

Thank you ☺️☺️

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If $\frac{1}{\sqrt{a}-\sqrt{b}}=\frac{1}{3}$ and $\frac{1}{\sqrt{a}+\sqrt{b}}=\frac{1}{2}$ then the difference of a and b is 6

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Given, $\frac{1}{\sqrt{a}-\sqrt{b}}=\frac{1}{3}$ → $\sqrt{a}-\sqrt{b}=3$ ----- (1)

And $\frac{1}{\sqrt{a}+\sqrt{b}}=\frac{1}{2}$ → $\sqrt{a}+\sqrt{b}=2$ --- (2)

We have to find difference of a and b.

Now, add (1) and (2)

$\sqrt{a}-\sqrt{b}=3$

$\sqrt{a}+\sqrt{b}=2$

Adding above two equations, we get,

$2 \sqrt{a}+0=2+3$

$\begin{array}{l}{2 \sqrt{a}=5} \\\\ {\sqrt{a}=\frac{5}{2}} \\\\ {a=\frac{25}{4}}\end{array}$

substitute $\sqrt{a}$ value in (2)

$\begin{array}{l}{\frac{5}{2}+\sqrt{b}=2} \\\\ {\sqrt{b}=\frac{2}{\sin \frac{5}{2}}} \\\\ {\sqrt{b}=\frac{4-5}{2}} \\\\ {\sqrt{b}=\frac{-1}{2}} \\\\ {b=\frac{1}{4}}\end{array}$