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Schach [20]
3 years ago
5

Identify the polynomials y^3y^3

Mathematics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

8

Step-by-step explanation:

Please thank me and rate this answer and give me brainliest please!

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A study will be conducted to investigate whether there is a difference in the mean weights between two populations of raccoons.
enyata [817]

Answer:

<h2>In this case,the answer would be option d) given in the answer choices or options or  A two-sample t-test for a difference between population means.</h2>

Step-by-step explanation:

  • In Statistics,a two sample test is generally used to examine or compare two different population means with the main objective to verify whether the population means are equal or otherwise.
  • The two sample t-test basically involves the hypothesis testing to determine or verify the equality between two concerned population means.
  • In this case,the two different populations of raccoons are given and the equality of the mean sample weights of the two distinct populations can be determined or evaluated by employing the hypothesis testing method under a two sample t test for measuring difference in two population means.
5 0
3 years ago
The percentage difference from 239,900 to 251,895
Katarina [22]

Answer:

4.87805%

Step-by-step explanation:

yuh yw

4 0
3 years ago
Read 2 more answers
-1/2x+12=-16 1/2 help<br> Plz I need it quick
Leokris [45]
Subtract 12 from both sides
- \frac{1}{2} x+12-12=-16 \frac{1}{2} -12- \frac{1}{2}x=-28 \frac{1}{2}
Divide by -\frac{1}{2} which means multiply by -2
x=-28 \frac{1}{2} *-2=57

Hope that helps

7 0
4 years ago
Yolanda is filling her bathtub. The table shows the number of gallons of water in the bathtub at different times since she start
Wittaler [7]

Answer:

Part A is 16.5

Step-by-step explanation:

Its crorect.

5 0
4 years ago
A new pop-up restaurant serving high-end street tacos just opened and is expected to have high demand based on the chef's prior
Harman [31]

Answer:

1. c

2. f

3. d

Step-by-step explanation:

This type of queuing model is an example of "single-channel, single-phase" process.

However, from the information given:

The inter-arrival rate = 10 customers per hour

Arrival time = 6 minutes

Service time = 5 minutes

∴

utilization = service time/arrival time

= 5/6

Time on queue T_q = p \times \dfrac{utilization }{1 - utilization} \times \dfrac{Cv_a^2 -Cv_b^2}{2}

T_q = 5 \times \dfrac{5/6 }{1 -5/6} \times \dfrac{(2.58^2 -0.75^2)}{2}

T_q = 25 \times 3.60945

T_q = 90.24 \\ \\ T_q \simeq 90 \ mins

Thus, customer waiting in the queue line is;

= \dfrac{T_q}{q}  \\ \\ = \dfrac{90}{6} \\ \\ \mathbf{=15}

Thus, new customers will have to wait in a total time of;

= waiting time + service time

= 90 + 5

= 95 minutes.

4 0
3 years ago
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