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Svetlanka [38]
3 years ago
15

Jacob is saving to buy an MP3 player that costs $195. He earns $225 a week at a part-time job. His expenses are $180 a week. If

he currently has saved $55, how many more weeks will it be before he can buy the MP3 player?
Mathematics
2 answers:
Paha777 [63]3 years ago
8 0

Jocab will take 4 more weeks to buy that MP3 player.

<u>Step-by-step explanation:</u>

Given:

Cost of MP3 player = $ 195

Earning per week = $ 225

Expenses per week = $ 180

To Find:

Weeks still required to save money for buying MP3 player.

Formula to be used:

Savings per week = Earning - Expenses

Solution:

Savings per week = Earning - Expenses

                              = $ 225 - $ 180     = $ 45

Already saved = $ 55

Need to save = $ 195 - $ 55 = $ 140

So for 4 weeks savings = $ 45 × 4 = $ 180

Thus Jocab will take 4 more weeks to buy that MP3 player.

s2008m [1.1K]3 years ago
5 0

Given:

Cost of MP3 player = $ 195

Earning per week = $ 225

Expenses per week = $ 180

To Find:

Weeks still required to save money for buying MP3 player.

Formula to be used:

Savings per week = Earning - Expenses

Solution:

Savings per week = Earning - Expenses

                              = $ 225 - $ 180     = $ 45

Already saved = $ 55

Need to save = $ 195 - $ 55 = $ 140

So for 4 weeks savings = $ 45 × 4 = $ 180

Thus Jocab will take 4 more weeks to buy that MP3 player.

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Consider an arbitrary ellipse x 2 a 2 + y 2 b 2 = 1. (Assume a, b &gt; 0.) (a) Find a parametrization of the ellipse using the d
uysha [10]

Answer:

α(t) = (-a*Sin(t), b*Cos (t))    where t ∈ [0, 2π]

Step-by-step explanation:

Given an arbitrary ellipse (x²/a²) + (y²/b²) = 1       (a, b > 0)

The parametrization can be as follows

x = -a*Sin(t)

y = b*Cos (t)

then

α(t) = (-a*Sin(t), b*Cos (t))    where t ∈ [0, 2π]

If  t = 0

α(0) = (-a*Sin(0), b*Cos (0)) = (0, b)

If  t = π/2

α(π/2) = (-a*Sin(π/2), b*Cos (π/2)) = (-a, 0)

If  t = π

α(π) = (-a*Sin(π), b*Cos (π)) = (0, -b)

If  t = 3π/2

α(3π/2) = (-a*Sin(3π/2), b*Cos (3π/2)) = (a, 0)

If  t = 2π

α(2π) = (-a*Sin(2π), b*Cos (2π)) = (0, b)

We can see the sketch in the pic.

7 0
3 years ago
Read 2 more answers
I'm confused I need help anyone
noname [10]
57-----------------------
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3 years ago
The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv
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Answer:

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=14.42 represent the sample mean

\mu population mean (variable of interest)

\sigma=6.95 represent the population standard deviation

n=36 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

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D

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