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barxatty [35]
3 years ago
14

Chang sees the following formula on a website about Newton’s second law. a = Sigma F over m.

Physics
2 answers:
nlexa [21]3 years ago
6 0

Answer:

He needs to find the net force acting on the object in a direction.

Explanation:

The second law of motion gives the relationship between force, acceleration and mass of an object. Its mathematical expression is given  by :

\Sigma F=m\Sigma a

\Sigma a=\dfrac{\Sigma F}{m}        

F represents the net force acting on the object. So, Chang needs needs to find the net force acting on the object in a direction. Hence, the correct option is (a).                  

Tems11 [23]3 years ago
4 0

Answer:A) he needs to find the net force acting on an object in a direction.

Explanation:

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Explained

Explanation:

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Here m = 0

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A 1-kilogram ball has 8 joules of kinetic energy.What is it speed?
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K.E=0.5*mv²
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3 0
3 years ago
A 50.0 kg object rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300 and
MariettaO [177]

Answer:

f=140\ N

Explanation:

Given:

  • mass of the object on a horizontal surface, m=50\ kg
  • coefficient of static friction, \mu_s=0.3
  • coefficient of kinetic friction, \mu_k=0.2
  • horizontal force on the object, F=140\ N

<u>Now the value of limiting frictional force offered by the contact surface tending to have a relative motion under the effect of force:</u>

F_s=\mu_s.N

where:

N= normal force of reaction acting on the body= weight of the body

F_s=0.3\times (50\times 9.8)

F_s=147\ N

As we know that the frictional force acting on the body is always in the opposite direction:

So, the frictional force will not be at its maximum and will be equal in magnitude to the applied external force and hence the body will not move.

so, the frictional force will be:

f=140\ N

8 0
3 years ago
A car with a mass of 1.50 X 10^3 kg starts from rest and accelerates to a speed of 18.0 m/s in 12.0 s. Assume that the force of
Serga [27]

The average power is 20.3 kW

Explanation:

First of all, we calculate the work done on the car: the work-energy theorem states that the work done on the car is equal to the change in kinetic energy of the car, so we have

W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2

where

W is the work done

K_i, K_f are the initial and final kinetic energy of the car

m=1.50\cdot 10^3 kg = 1500 kg is the mass of the car

u = 0 is the initial velocity

v = 18.0 m/s is the final velocity

Substituting,

W=\frac{1}{2}(1500)(18)^2=2.43\cdot 10^5 J

Now we can find the average power developed by the car's engine, which is given by

P=\frac{W}{t}

where

W=2.43\cdot 10^5 J is the work done

t = 12.0 s is the time taken

Substituting,

P=\frac{2.43\cdot 10^5 J}{12.0}=20,250 W = 20.3 kW

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

4 0
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