When conducting a search to identify a text's credibility and reliability, you have to check the following characteristics:
- Sources: where the information is obtained and it is supposed to be true. It is said that you need at least three different sources that explain the same information for it to be validated.
- Is the article is current?: articles could change all the time, specially scientific ones because new discoveries can change what was discovered before, so it is important to check if the text you are reading is current or not, and if it is not, you need to check if something has changed during all those years.
<h3>Article's credibility</h3>
In this exercise, you have to present an article and describe the purpose of the source and if the article is current or not.
For example, let's select an article called "How using social media affects teenagers".
The purpose of the sources in this article is to demonstrate how social media affects teenagers using different surveys.
Check more information about sources here brainly.com/question/24708478
Answer:
139.6m/s
Explanation:
Calculate the tension first, T=m*g
mass(m): 1750kg, gravity(g): 9.8m/s^2
T= 1750*9.8
=17150N
Then calculate the wave speed using the equation v = √ (T/μ)
v= √(17150N)/(0.88kg/m)
=139.6m/s
Answer:
Height h= 1.7 m
Explanation:
Supposing we have to find height in meter.
1 feet = 0.3048 m
1 inch = 0.0254 m
Given that:
5 feet
= 5×0.3048
= 1.524 m
and 7 inch = 7×0.0254= 0.1778 m
Therefore total height of a man in meter
5 feet 7 inch = 1.5424+0.1778 =1.7 m
Height h= 1.7 m
<span>i think the answer is : Bend the arm at the elbow with the back straight </span>
Answer:
2.56 m/s²
Explanation:
A standing wave is produced in the wire, its frequency f = n/2l√(T/μ). For the fundamental frequency, n = 1.
f = 1/2l√(T/μ)
where l = length of wire = 1.60 m, T₁ = tension in wire = weight of object = m₁g (neglecting wires mass), m₁ = mass of object = 3.00 kg, g = acceleration due to gravity on the small planet, μ = linear density of wire = m₀/l , m₀= mass of wire = 4.30 g = 0.0043 kg and f = 1/T where T = period of pulse = 59.9 ms = 0.0599 s
f = 1/2l√(T₀/μ) = 1/T ⇒ T₁ = 4l²μ/T²
m₁g = 4l²μ/T²
g = 4l²μ/m₁T² = 4l²m₀/l/m₁T² = 4lm₀/m₁T²
g = 4lm₀/m₁T² = 4 × 1.60 × 0.0043/(3.00 × 0.0599²) = 2.56 m/s²
