Keisha writes that if an object has any external forces acting on it, then the object can be in dynamic equilibrium but not
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Answer:
The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N
(b) the force the light beam exerts is much too small to be felt by the man.
Explanation:
Given;
cross-sectional area of the man, A = 0.500m²
intensity of light, I = 35.5kW/m²
If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;
P = I/c
where;
P is the pressure of the incident light
I is the intensity of the incident light
c is the speed of light
F = PA
where;
F is the force of the incident light on the man
P is the pressure of the incident light on the man
A is the cross-sectional area of the man
F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N
The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N
Therefore, the force the light beam exerts is much too small to be felt by the man.
Density = Mass per unit Volume
that is,
D = m / V
Now,
We've been provided with,
Density = 790 kg/m³
Volume = 1250 litres = 1.250 m³
Now,
987.5 kg of mass will a 1250 litres tank will hold.
Please Mark It As Brainliest Answer_
that is,
D = m / V
Now,
We've been provided with,
Density = 790 kg/m³
Volume = 1250 litres = 1.250 m³
Now,
987.5 kg of mass will a 1250 litres tank will hold.
Please Mark It As Brainliest Answer_