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Reptile [31]
3 years ago
11

The scatterplot and trend line show the correlation

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
8 0

Answer:

y = 3x + 55

Step-by-step explanation:

I just took the test

alekssr [168]3 years ago
3 0

Answer:2

Step-by-step explanation:

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The value of y varies directly with x. When y=3,x=15 what is the value of y when y=10
Yuki888 [10]
If you mean the x, it would be 50
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3 years ago
X-5y = 0, y +1=3(x+5)<br> Determine whether the lines are parallel, intersect, or coincide
Vinvika [58]
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4 0
3 years ago
An open top rectangular box with a square bottom has a volume of 120 cubic meters. Its bottom and sides are made from two differ
denpristay [2]

Answer:

The dimensions that minimizes the cost are a= 6.604 (lenght of a side) and h=2.752 (height)

Step-by-step explanation:

Let's define some notation first:

h = represent the height of the box

a= length of a side on the bottom

We need to remember that we have on this case an open box, so then we don't have a top part.

Let's begin with the formula for the volume of the box, we have a total volume given of 120m^3, and we know that the volume for a box is the product of the area and the height like this:

120 m^3 = a^2 h   (1)

From equation (1) we cna solve for the height and we got:

h=\frac{120}{a^2}   (2)

Now let's move to th surface area formula. The top bottom area is a^2 and the surface area for the four lateral sides is 4ah. Since we know that the cost for the bottom material is 10 $ per each square meter and for the sides is 12$ per square meter we can create a function cost like this:

Cost= Cost of  bottom+ Cost of sides

Cost = 10a^2 + (12)(4ah) = 10a^2 + 48ah   (3)

Now we can substitute into equation (3) the equation (2) like this:

Cost = 10a^2 + (12)(4ah) = 10a^2 + 48a\frac{120}{a^2}=10a^2 +\frac{5760}{a}   (4)

Now in order to find the minimum cost, we can take the first derivate for the expression (4) like this

\frac{d}{da} Cost = 20a -\frac{5760}{a^2}

We can set this equal to 0 and solve for a and we got:

\frac{5760}{a^2}= 20a

\frac{5760}{20}=a^3

a=6.604

And since we have a we can find h using the expression (2) like this:

h=\frac{120}{a^2}=\frac{120}{6.604^2}=2.752  

So then the dimensions that minimizes the cost are a= 6.604 (lenght of a side) and h=2.752 (height)

6 0
3 years ago
I need answers for this.
WARRIOR [948]

Answer:

18, 24, 8, 3

Step-by-step explanation:

8a = 42 - 18

8a = 24

a = 24 / 8

a = 3

To check, plug 3 into the equation

8(3) = 42-18

24 = 24

7 0
3 years ago
Read 2 more answers
Simplify 3 square root of 5 end root minus 2 square root of 7 end root plus square root of 45 end root minus square root of 28
Lana71 [14]
Hello,

3 \sqrt{5} -2 \sqrt{7} + \sqrt{45} - \sqrt{28}\\\\&#10;= 3 \sqrt{5} -2 \sqrt{7} + 3\sqrt{5} - 2\sqrt{7}\\\\&#10;=6 \sqrt{5} -4 \sqrt{7} &#10;



6 0
3 years ago
Read 2 more answers
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