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dusya [7]
2 years ago
10

3. In the figure below, E is on AD and C is on BD. The dimensions given are in meters. What is the length, in meters, of CD?

Mathematics
1 answer:
damaskus [11]2 years ago
7 0

Answer:

C. 3,960

Step-by-step explanation:

∆ADB ~ ∆EDC. Therefore,

\frac{AB}{EC} = \frac{DB}{DC}

\frac{2,000}{1,200} = \frac{2,640 + x}{x} (substitution)

Solve for x

\frac{5}{3} = \frac{2,640 + x}{x}

Cross multiply

5*x = 3(2,640 + x)

5x = 7,920 + 3x

5x - 3x = 7,920

2x = 7,920

x = 7,920/2

x = 3,960 meters

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Answer:

The true statements are:

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The given data are:  35, 41, 18, 75, 36, 21, 62, 29, 154, 70

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If we divided the data to two groups , they will be:

(18 , 21 , <u>29 </u>, 35 , 36)  ,  (41 , 62 , <u>70 </u>, 75 , 154)

So, The lower quartile Q1 is the median of the first group = 29

And the upper quartile Q2 is the median of the second group = 70

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