3 years ago

I need help o this problem

Mathematics

1 answer:

drek231 [11]3 years ago

8 0

A If im not mistaken but that is what i would go with

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The starting temperature was 24°.

Goryan [66]

Answer:

-10 degrees

Step-by-step explanation:

24+8=32

32-(7 x 6)= 32-42=-10

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3 years ago

(2^8 x 3^−5 x 6^0)−2 x 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 x 2^28

Veronika [31]

$(2^8\cdot3^{-5}\cdot6^0)^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot2^{28}\\\\=(2^8)^{-2}\cdot(3^{-5})^{-2}\cdot1^{-2}\cdot\dfrac{(3^{-2})^4}{(2^3)^4}\cdot2^{28}\\\\=2^{-16}\cdot3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot2^{28}\\\\=2^{-16}\cdot2^{28}\cdot2^{-12}\cdot3^{10}\cdot3^{-8}\\\\=2^{-16+28+(-12)}\cdot3^{10+(-8)}\\\\=2^0\cdot3^2=1\cdot9=\boxed{9}\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}\\\\a^{-n}=\dfrac{1}{a^n}$

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4 years ago

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The height of a candle, in centimeters, can be modeled by the linear equation h = 28 - 2t, where t represents the hours that the

Ostrovityanka [42]

The slope is -2. In context to this problem, the candle will burn away 2cm of its length every hour.

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3 years ago

Angle Q = 85° Determine angle O.

kkurt [141]

Answer:

∠O = 95°

Step-by-step explanation:

since ∠Q = 85°, arc NOP = 2(85°) = 170°

arc PQN = 360° - arc NOP

arc PQN = 360° - 170° = 190°

∠O = 1/2(arc PQN) = 1/2(190°) = 95°

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3 years ago

What's the answer to this 94<-2(1+6b)

tigry1 [53]

Answer:

-8 > b

Step-by-step explanation:

94<-2(1+6b)

Distribute

94<-2-12b

Add 2 to each side

94+2<-2-12b +2

96 < -12b

Divide each side by -12, remembering to flip the inequality since we divide by a negative

96/-12 > -12b/-12

-8 > b

5 0

3 years ago