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4 years ago

I need help o this problem

Mathematics

1 answer:

drek231 [11]4 years ago

8 0

A If im not mistaken but that is what i would go with

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the equation is -2x² = 4-3 (x + 1) and the question is justify that it is a 2nd degree equation with the unknown x complete.

Serggg [28]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equation

-2x² = 4-3 (x + 1)

-2x² = 4-3x-3

-2x² = -3x -7

0 = 2x² -3x -7

We know that the degree of the equation is the highest power of x variable in the given equation.

In the equation 0 = 2x² -3x -7 the highest power of x variable in the given equation is 2.

Thus, the degree of the equation is 2.

Also in the equation 0 = 2x² -3x -7, the unknown variable is 'x'.

Let us determine the value 'x'

2x² -3x -7 = 0

Add 7 to both sides

$2x^2-3x-7+7=0+7$

$2x^2-3x=7$

Divide both sides by 2

$\frac{2x^2-3x}{2}=\frac{7}{2}$

$x^2-\frac{3x}{2}=\frac{7}{2}$

Add (-3/4)² to both sides

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{7}{2}+\left(-\frac{3}{4}\right)^2$

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{65}{16}$

$\left(x-\frac{3}{4}\right)^2=\frac{65}{16}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{3}{4}=\sqrt{\frac{65}{16}}$

$x-\frac{3}{4}=\frac{\sqrt{65}}{\sqrt{16}}$

$x-\frac{3}{4}=\frac{\sqrt{65}}{4}$

Add 3/4 to both sides

$x-\frac{3}{4}+\frac{3}{4}=\frac{\sqrt{65}}{4}+\frac{3}{4}$

$x=\frac{\sqrt{65}+3}{4}$

similarly solving

$x-\frac{3}{4}=-\sqrt{\frac{65}{16}}$

$x=\frac{-\sqrt{65}+3}{4}$

So the solution of the equation will have the values of x such as:

$x=\frac{\sqrt{65}+3}{4},\:x=\frac{-\sqrt{65}+3}{4}$

6 0

3 years ago

The radius of the base of a cylinder is 10 centimeters, and its height is 20 centimeters. A cone is used to fill the cylinder wi

Leya [2.2K]

Answer: 24times

Step-by-step explanation:

Formula for the volume of a cylinder = πr²h

Volume of the cone = 1/3πr²h

Therefore the volume of the cylinder = 22/7 x 10² x 20

= 22/7 x 10 x 10 x 20

= 6285.71cm³

Therefore , the volume of the cone = 1/3 x 22/7 x 5² x 10

= 1/3 x 22/7 x 5 x 5 10

= 5500/21

= 261.9cm³

Therefore the number of times needed to use the completely filled cone to completely filled the cylinder with water = 6285.71/261.9

= 24times.

8 0

4 years ago

Find the equation of the line which passes through (-2,-2) and (2, -4).

Lana71 [14]

It should be B

Calculate the slopes using the change of y over the change in x

-2/2=-1

That’s the only option with a slope of -1

8 0

3 years ago

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What is the number real positive?

san4es73 [151]

Real positive numbers are decimal numbers, not limited to integers, which are above zero.

4 0

3 years ago

Between wich two consecutive whole numbers would 12 be located at?

Ierofanga [76]

I'm not 100% sure, but I'm pretty sure its 11 and 13

8 0

3 years ago