1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
amid [387]
3 years ago
7

What is combined mean

Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0
Combined in mathematics is to add together to find a total. If you combine 1 and 2 you get 3.
You might be interested in
Can somebody please help me !!!!!!
Katarina [22]
So, looking at how many seniors there are, you can see that there are 35 of them. 25 are in sports, 5 are in music/drama, and 5 work. If you added them altogether, you get 35. Now, the chance of them being in sports is 25/35 chance/probability. You can simplify 25/35 because both of them are divisible by 5. 5 times 5= 25 and 7 times 5=35. Therefore, the answer is 5/7.
5 0
3 years ago
Investigate the range of each parent function below over the interval o ranges from least to greatest.<br> Identity function, re
Y_Kistochka [10]

Answer:

Here we have the domain:

D = 0 < x < 1

And we want to find the range in that domain for:

1) y = f(x) = x

First, if the function is only increasing in the domain (like in this case) the minimum value in the range will match with the minimum in the domain (and the same for the maximums)

f(0) = 0 is the minimum in the range.

f(1) = 1 is the maximum in the range.

The range is:

0 < y < 1.

2) y = f(x) = 1/x.

In this case the function is strictly decreasing in the domain, then the minimum in the domain coincides with the maximum in the range, and the maximum in the domain coincides with the minimum in the range.

f(0) = 1/0 ---> ∞

f(1) = 1/1

Then the range is:

1 < x.

Notice that we do not have an upper bound.

3) y = f(x) = x^2

This function is strictly increasing, then:

f(0) = 0^2 = 0

f(1) = 1^2 = 1

the range is:

0 < y < 1

4) y = f(x) = x^3

This function is strictly increasing in the interval, then:

f(0) = 0^3 = 0

f(1) = 1^3 = 1

the range is:

0 < y < 1.

5) y = f(x) = √x

This function is well defined in the positive reals, and is strictly increasing in our domain, then:

f(0) = √0 = 0

f(1) = √1 =1

The range is:

0 < y < 1

4 0
3 years ago
Find the slope of the line 25 POINTS WILL MARK BRANLIST
UNO [17]

Answer:

-7/4

Step-by-step explanation:

6 0
3 years ago
Pl hell any thing is appreciated I will give Brainly
Zarrin [17]

Answer:

First one and last one

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
This is an accounting question: On September 23, Reese Company received a $350 check from Mike Moluf for services to be performe
svlad2 [7]

Not to seem rude, but you might have better luck in Business. Unless someone here know accounting lol

3 0
3 years ago
Other questions:
  • Ellen has $75 in her savings account. She deposits $25 every week. Her father also deposits $35 into the account every time Elle
    13·2 answers
  • It is legal to write a check when your account does not have funds to cover it. True False
    10·2 answers
  • 5x680 in the Distributive property
    8·1 answer
  • the student to faculty ratio at a small college is 17:3. the total of students and faculty is 740. how many faculty members are
    10·2 answers
  • The cost of three tickets to a movie is at least $20. Select an inequality that represents the cost x (in dollars) of each ticke
    11·1 answer
  • Determine the intercepts of the line.
    11·1 answer
  • Danielle earns a 7.25% commission on everything she sells at the electronic store where she works . she also earns a base salary
    11·1 answer
  • Ads Galore makes posters with standard dimensions of 8 and 1 over 2 inches by 11 inches as shown. What is the smallest acceptabl
    9·1 answer
  • Someone help pleasee
    9·2 answers
  • Complete the input-output table that represents the linear function y=-4x+10
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!