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3 years ago

Slope: -5, y-intercept:3

Mathematics

2 answers:

Sati [7]3 years ago

6 0

Whats the question?

Anastasy [175]3 years ago

4 0

Answer:

y = -5x + 3

ABOUT SLOPE INTERCEPT FORM:

y = mx + b
b is the y - intercept AKA the starting point
m represents the slope

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The difference of 20 and x

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Answer:

20-x

Step-by-step explanation:

you need the value of x to answer

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3 years ago

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3 years ago

Simplify (2√27) x (3√32)

Kryger [21]

For this case we have the following expression:

$(2 \sqrt {27}) (3 \sqrt {32})$

We have to:

$27: 3 * 3 * 3: 3 ^ 2 * 3\\32: 16 * 2: 4 ^ 2 * 2$

Rewriting the expression and simplifying we have:

$(2 \sqrt {3 ^ 2 * 3}) (3 \sqrt {4 ^ 2 * 2}) =\\(2 * 3 \sqrt {3}) (3 * 4 \sqrt {2}) =\\(6 \sqrt {3}) (12 \sqrt {2}) =\\72 \sqrt {3 * 2} =\\72 \sqrt {6}$

Answer:

$72 \sqrt {6}$

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4 years ago

Read 2 more answers

How to draw a model to show a fraction that is equivalent to 1/3 and a fraction that is not equivalent to 1/3

kakasveta [241]

Sorry! I can't find one that is not equivalent to 1/3. Only equivalent.

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3 years ago

Find a formula for the product P of the solutions of the quadratic equation ax²+bx+c=0 .

Ede4ka [16]

Answer:

product of the roots= c/a

Step-by-step explanation:

The the two roots(α and β) of the quadratic equation ax²+bx+c=0 as given by shridharacharya formula are

$\alpha= \frac{-b+\sqrt{b^2-4ac} }{2a}$

$\beta= \frac{-b-\sqrt{b^2-4ac} }{2a}$

now product of the roots

αβ= $\frac{-b+\sqrt{b^2-4ac} }{2a}$ × $\frac{-b-\sqrt{b^2-4ac} }{2a}$

use formula (a+b)(a-b)= a^2-b^2 and solve we get

αβ= c/a

therefore product of the roots= c/a

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4 years ago