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2 years ago

Please answer this will mark brainliest

Mathematics

2 answers:

Tomtit [17]2 years ago

5 0

The answer is 5/9. You can check this by dividing 5 by 9 on a calculator and you’ll get a number similar to:

0.555555556

Hope this helps!! :)

OlgaM077 [116]2 years ago

4 0

Answer:

5/9

Step-by-step explanation:

You might be interested in

b. Find a 99% confidence interval for mean age of ICU patients using the facts that, in the sample, the mean is 57.55 years and

rjkz [21]

Answer:

99% of confidence intervals for mean age of ICU patients

(53.8920 , 61.2079)

Step-by-step explanation:

Explanation:-

Given sample mean $x^{-} = 57.55$

Given standard error is determined by

S.E = $\frac{S.D}{\sqrt{n} }$

Given data standard error = 1.42

99% of confidence intervals for mean is determined by

$(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.01} \frac{S.D}{\sqrt{n} } )$

$Z_{\frac{\alpha }{2} } = Z_{\frac{0.01}{2} } = Z_{0.05} = 2.576$

$(x^{-} - 2.576 S.E , x^{-} + 2.576 S.E)$

$(57.55 - 2.576X 1.42 , 57.55+ 2.576 X1.42)$

(53.8920 , 61.2079)

Conclusion:-

99% of confidence intervals for mean is determined by

(53.8920 , 61.2079)

5 0

3 years ago

-4/5 + 4/5 Please I need the grade

KATRIN_1 [288]

Answer:

0 hope it helps ok bye have a good grade

8 0

3 years ago

Read 2 more answers

What are the coordinates of the vertex of the parabola described by the

ICE Princess25 [194]

Step-by-step explanation:

please type the question properly

3 0

3 years ago

Read 2 more answers

The average performance rating of the employees at Company A is 6.5 on a scale from 1 to 10 (10 being highest). The standard dev

djyliett [7]

Answer:

The best choice would be hiring a random employee from company A

Step-by-step explanation:

Supposing that the performance rating of employees follow approximately a normal distribution on both companies, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.

In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings

The z-value corresponding to company A is

$z=\frac{\bar x-\mu}{s}$

where

$\bar x$ = mean of company A

$\mu$ = 5.5 (average of rating between 1 and 10)

s = standard deviation of company A

$z=\frac{\bar x-\mu}{s}=\frac{6.5-5.5}{2.1}=0.7142$

We do the same for company C

$z=\frac{\bar x-\mu}{s}=\frac{7.4-5.5}{6.8}=0.2794$

This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a performance rating > 5.5.

So, the best choice would be hiring a random employee from company A

4 0

3 years ago

Let me see some q,,,,,,,,,,,,,,,

Dafna11 [192]

Step-by-step explanation:

huh??????????????????

3 0

3 years ago