Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
The question is a bit confusing, but I'm assuming you are adding them all up, so the total sum would be 60 items :)
Answer:
1017/100
Step-by-step explanation:
68
%
=
17
25
Explanation:
68
% = 68/100
=68/100÷4
=17/25
And finally we have:
1.050 as a fraction equals 105/100
105÷17=6.17
100÷25=4
6.17+4=10.17
And finally we have:
10.17 as a fraction equals 1017/100
You would solve for Y and then for X and you would get the awncer
Answer:
3, 4, 5
Step-by-step explanation:
I like to let x represent the middle integer. Then the first is x-1 and the third is x+1. The given relation is ...
(x-1)^2 +2x = 4(x+1) -3
We can put this equation into standard form and solve.
x^2 -2x +1 +2x = 4x +4 -3
x^2 -4x = 0 . . . . . subtract 4x+1
x(x -4) = 0
So, x=0 is a solution to the equation, but an extraneous solution with respect to the problem.
x = 4 is also a solution to the equation, indicating the integers are 3, 4, 5.
_____
<em>Check</em>
3^2 +2·4 = 4·5 -3
17 = 17 . . . . answer checks OK
