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3 years ago

I Obviously don't need help but here's a survey answer and you will receive 10 points, Here you go:

Mathematics

2 answers:

DerKrebs [107]3 years ago

6 0

Turbo chips...............................................................................

sineoko [7]3 years ago

3 0

Oven baked hot cheetos

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Mary has a third of the money that Erin has. Erin has $8 less than John. Together they have $267. How much money does each of th

svet-max [94.6K]

Mary = (1/3)x

Erin = x - 8

John = x

Here is your equation:

(1/3)x + (x - 8) + x = 267

Take it from here.

5 0

3 years ago

Read 2 more answers

Ten pieces of candy are in a bag. They all have the same shape; but 2 pieces are butterscotch flavored, 5 pieces are

gayaneshka [121]

Answer:

$\frac{4}{5}$

Step-by-step explanation:

4 0

3 years ago

Use the identity below to complete the tasks: a3 − b3 = (a − b)(a2 + ab + b2) When using the identity for the sum of two cubes t

saveliy_v [14]

Answer:

a= $5q^ {2}$

b= $r^{2}s$

Step-by-step explanation:

Here $125q^{6}$ is like the $a^{3}$ in the general formula.

So we can write $125q^{6}$ as:

$(5q^ {2} )^{3}$

We can also write $r^{6} s^{3}$ as:

$(r^{2}s)^{2}$

Therefore:

a³= $(5q^ {2} )^{3}$

b²= $(r^{2}s)^{2}$

8 0

3 years ago

Read 2 more answers

Plz help ........................

marysya [2.9K]

I will help you but I have a question

3 0

3 years ago

1) AU (C - B) =

torisob [31]

Answer:

$A \cup (C-B) = (A \cup C) \cap (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C = A \cup (B \cup C)\\B^c \cap (A-C) = (B^c - C) \cap A\\(B \cap C) - A = (B-A)\cap C\\C-(A\cup B) = (C - A )\cap B\\A^c \cap (B \cap C) = ( A^c \cap B) \cap C$

Step-by-step explanation:

$A \cup (C-B) = A \cup (C \cap B^c) = (A \cup C) \cap (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C = (A \cup B ) \cup C = A \cup (B \cup C)\\B^c \cap (A-C) = B^c \cap (A \cap C^c) = (B^c \cap C^c) \cap A = (B^c - C) \cap A\\(B \cap C) - A = (B \cap C) \cap A^c = (B \cap C) \cap A^c = (B \cap A^c)\cap C = (B-A)\cap C\\C-(A\cup B) = C \cap (A\cup B)^c = C \cap (A^c \cap B^c ) = (C \cap A^c )\cap B^c = (C - A )\cap B\\$

$A^c \cap (B \cap C) = ( A^c \cap B) \cap C$

3 0

4 years ago