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Pavel [41]
3 years ago
6

What is the multiplicative rate of change of the function

Mathematics
2 answers:
mario62 [17]3 years ago
5 0

Answer: B \frac{2}{3}


Step-by-step explanation:

From the given table

When x changes from 1 to 2 , value of y changes from 6 to 4

The multiplicative rate of change=\frac{4}{6}=\frac{2}{3}

Similarly we can check

When x changes from 2 to 3 , value of y changes from 4 to \frac{8}{3}

The multiplicative rate of change=\frac{\frac{8}{3}}{4}=\frac{2}{3}

When x changes from 3 to 4 , value of y changes from  \frac{8}{3} to  \frac{16}{9}

The multiplicative rate of change=\frac{\frac{16}{9}}{\frac{8}{3}}=\frac{2}{3}

Therefore, the multiplicative rate of exponential function = \frac{2}{3}


solong [7]3 years ago
3 0

Answer:

B. \frac{2}{3}

Step-by-step explanation:

We have been given a table of values. We are asked to find the multiplicative rate of change of our given function.

Table:

x         y

1         6

2        4

3        8/3

4         16/9

We know that the multiplicative rate of change of a function is the number by which each next term of an exponential function is increasing or decreasing.

We can find multiplicative rate of change by dividing any term of the function by its previous term.

\text{Multiplicative rate of change}=\frac{4}{6}=\frac{2}{3}

\text{Multiplicative rate of change}=\frac{16}{9}\div\frac{8}{3}=\frac{16}{9}\times\frac{3}{8}=\frac{2}{3}

Therefore, the multiplicative rate of change of our given function is \frac{2}{3} and option B is the correct choice.

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The local train heading for Westford at 60km/h and the express train heading for Eastford at 80 km/h pass each other at Centervi
Wewaii [24]

Answer:

The maximum distance to the nearest kilometer between Westford and Centerville is 111.43 km.

Step-by-step explanation:

Local train stats:

Rate = 60 km/h

Distance = x km

Time = x/60 hours

Express train stats:

Rate = 80 km/h

Distance = (195-x) km

Time = (195-x)/80 hours

Now we will equate both the times.

x/60 =(195-x)/80

x/3= (195-x)/4

4x= 585-3x

7x= 585

x = 83.57 km

195-x=195-83.57= 111.43 km

Hence, the maximum distance to the nearest kilometer between Westford and Centerville is 111.43 km.

3 0
3 years ago
Please Help me!!! <br><br><br> I know the answer but I don’t understand how to get that answer
worty [1.4K]
-7 ÷ 2 1/2
Okay, so first, put the -7 over one and make 2 1/2 an improper fraction. so now:
-7/1 ÷ 5/2
Then, take the reciprocal of 5/2 and multiply it by -7/1
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5 0
3 years ago
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Sati [7]
Perpendicular: slope is -3/2

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3 0
2 years ago
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A room contains three urns: u1, u2, u3. u1 contains 3 red and 2 yellow marbles. u2 contains 3 red and 7 yellow marbles. u3 conta
Archy [21]

Answer:

\dfrac{11}{30}

Step-by-step explanation:

Urn U1: 3 red and 2 yellow marbles, in total 5 marbles.

The probability to select red marble is \dfrac{3}{5}=0.6.

Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

The probability to select red marble is \dfrac{3}{10}=0.3.

Urn U1: 1 red and 4 yellow marbles, in total 5 marbles.

The probability to select red marble is \dfrac{1}{5}=0.2.

The probability to choose each urn is the same and is equal to \frac{1}{3}.

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\dfrac{1}{3}\cdot 0.6+\dfrac{1}{3}\cdot 0.3+\dfrac{1}{3}\cdot 0.2=\dfrac{1.1}{3}=\dfrac{11}{30}.

4 0
3 years ago
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