6x – 8 = 4 written as a system. Hence second option is correct
<u>Solution:</u>
Given, equation is 6x – 8 = 4.
We have to find the equivalent system from given options.
First let us solve given equation, 6x – 8 = 4 ⇒ 6x = 4 + 8 ⇒ 6x = 12 ⇒ x = 2
Now, let us solve one by one option ,so that when we get above solution, that is correct option.
- y = 6x – 8 and y = -4 ⇒ put y = -4 in y = 6x – 8 ⇒ 6x – 8 = -4 ⇒ 6x = 8 – 4
⇒ 6x = 4 ⇒ x ≠ 2, wrong option
- y = 6x – 8 and y = 4 ⇒ put y = 4 in y = 6x – 8 ⇒ 6x – 8 = 4 ⇒ 6x = 8 + 4 ⇒ 6x = 12 ⇒ x = 2, right option.
- y = -6x + 8 and y = 4 ⇒ put y = 4 in y = -6x + 8 ⇒ -6x + 8 = 4 ⇒ 6x = 8 – 4 ⇒ 6x = 4 ⇒ x ≠ 2, wrong option
hence, second option is correct.
System of Linear Equations entered :
[1] y - 2x/3 = -1
[2] y + x = 4
// To remove fractions, multiply equations by their respective LCD
Multiply equation [1] by 3
// Equations now take the shape:
[1] 3y - 2x = -3
[2] y + x = 4
Graphic Representation of the Equations :
-2x + 3y = -3 x + y = 4
Solve by Substitution :
// Solve equation [2] for the variable x
[2] x = -y + 4
// Plug this in for variable x in equation [1]
[1] 3y - 2•(-y +4) = -3
[1] 5y = 5
// Solve equation [1] for the variable y
[1] 5y = 5
[1] y = 1
// By now we know this much :
y = 1
x = -y+4
// Use the y value to solve for x
x = -(1)+4 = 3
I hope this help you
Answer:
Step-by-step explanation:
She added 3x and -2x, getting 5x, instead of x. She needs to pay more attention to the positive/negative signs.
This function would have a maximum.
Since we are subtracting by a -4 for each increase in x, we know that the numbers will continue to go down. Given this fact, we know the number will never be higher than when we started, but the number could go infinitely low. As a result we have a maximum and no minimum.
