Answer:
a) P(X=41)= 0.0086 = 0.86%
b) P(36≤X≤38)== 0.1215 = 12.15%
c) would be unusual that fewer that 20 murders were cleared because P(X≤20) = 0.000081 =0.0081%
Step-by-step explanation:
if the random variable X= number of cleared murders , then X follows a binomial distribution:
P(X=x)= n!/[(n-x)!*x!]*p^x*(1-p)^(n-x)
where P(X=x)= probability of x cleared murders, n= number of murders selected=50 , p= probability for a murder to be cleared (67%)
therefore
a) P(X=41)=50!/[(50-41)!*41!]*0.67^41*0.33^(50-41)= 0.0086
b) P(36≤X≤38)= P(X≤38) - P(X≤36) = 0.9371- 0.8156 = 0.1215
c) P(X≤20) = 0.000081
therefore would be unusual that fewer that 20 murders were cleared
Answer:
63 and 53
Step-by-step explanation:
you could use trail and error. So:
13+23=9
33+43=91
63+73=559
53+63=341
Answer:
Step-by-step explanation:
660 inches
Answer:
A, B, and C are all true.
Step-by-step explanation:
A. 6 is neither a perfect square nor a perfect cube. True
B. 16 is a perfect square. True 
C. 27 is a perfect cube. True 
OD. 1,331 is both a perfect square and a perfect cube. False
E. 9 is a perfect cube. False
Answer:
26 bags
Step-by-step explanation:
A bag of cat chows = 30 lbs
Amount of cat chows needed in a week = 15 lbs = ½ bag of cat chow
There are at least 52 weeks in a year.
The least number of cat chows bags needed at the shelter in 1 year = 52 weeks × ½ bag of chow
= 52 × ½
= 52/2
= 26 bags of cat chow
At least, 26 bags would be needed in 1 year (52 weeks) at this wild life shelter if 15 lbs is consumed weekly.
