Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
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Answer:
<h2>20</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
- a straight line contains 180°
<h3>let's solve:</h3>
according to the question
7x+x+20=180
=>8x+20=180
=>8x=160
therefore
x=20
Answer:
x
−
y
= −
11
Step-by-step explanation:
Hey!
so for the first one its 60°, and for the second one its 1/6
<span>Simplifying
4x2 + 8xy + 4y2
Reorder the terms:
8xy + 4x2 + 4y2
Factor out the Greatest Common Factor (GCF), '4'.
4(2xy + x2 + y2)
Factor a trinomial.
4((x + y)(x + y))
Final result:
4(x + y)(x + y)</span>