Given the parents AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the pro
geny will be expected to phenotypically resemble the AABBCc parent? Given the parents AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the progeny will be expected to phenotypically resemble the AABBCc parent? 1 1/8 3/8 1/4 3/4
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
F1 genotypes: 1/2 AA, 1/2 Aa
F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
F1 genotypes: 1 Bb
F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
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The multicellular sporophyte of bryophytes turns a single fertilization event into thousands new haploid individual(s), whereas fertilization in Chara and Coleochaete leads to four new haploid individual(s).
