Given the parents AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the pro
geny will be expected to phenotypically resemble the AABBCc parent? Given the parents AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the progeny will be expected to phenotypically resemble the AABBCc parent? 1 1/8 3/8 1/4 3/4
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
F1 genotypes: 1/2 AA, 1/2 Aa
F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
F1 genotypes: 1 Bb
F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
Because many animals and situations include an animal that has been poisoned by maybe eating the wrong thing and if you don’t know how to treat toxicology many animals could die
Bacteria has a primitive type of RNA polymerase while archaeal RNA ploymerase is more advanced and complex than that of bacterial. The structure of archaeal RNA ploymerase has more resemblance with RNA polymerase II of eukaryotes. The RNA polymerase of bacteria requires sigma factor for transcription initiation whereas the RNA ploymerase of archaea requires transcription factors for transcription initiation just like eukaryotes.
