3 years ago

Use 1 as a benchmark to compare 6/5 and 5/6

Mathematics

1 answer:

Rashid [163]3 years ago

8 0

6/5 is greater than one by 1/5 while 5/6 is less than one by 1/6.

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Please answer fast!!!!!

BlackZzzverrR [31]

Answer:

x = 2

Step-by-step explanation:

note that 4096 = $8^{4}$ , then

$8^{2x}$ = $8^{4}$

Since bases on both sides are equal, both 8 , then equate the exponents

2x = 4 ( divide both sides by 2 )

x = 2

6 0

3 years ago

Read 2 more answers

Is this true? And also how does the equation from y-3=3(x-4) become a positive <br> y+3=3x-12?

EastWind [94]

Step-by-step explanation:

the right equation is :

y-y1=m(x-x1)

y+3=3(x+4)

y+3= 3x+12

y=3x+12-3

y=3x+9

7 0

3 years ago

a number is selected at random from set (2,3,45,6,7,8,9,and 10). which event covers the entire sample space of this experiment ?

ki77a [65]

I'm not sure I understand the question. Is this worded correctly?

8 0

4 years ago

Nguyen played a game in which he could either lose or gain points each round. at the end of 7 rounds, he had -8 points. After on

Sergeeva-Olga [200]

Answer:

I think the answer would be +15.

Step-by-step explanation:

3 0

2 years ago

In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad

weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

$\angle acd = 60 ^{\circ}$

Therefore, we have

$\angle dcb =90- 60= 30 ^{\circ}$

Now, in triangle bcd, we have

$\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3$

Now, in triangle acb, we have

$tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3= \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15$

Thus, ad is 15 cm.

4 0

3 years ago