All categories

3 years ago

Please answer my question! (^• ω •^)∫

Mathematics

2 answers:

kiruha [24]3 years ago

5 0

The answer to this is D

algol [13]3 years ago

3 0

Since you have a 10 x 10 grid, there are 100 squares which then equal 1 percent each (since each square is 1/100 of the grid). To have 60% you would need 60 squares shaded.

You might be interested in

Is -1 part of the set of whole numbers

s2008m [1.1K]

No. The whole numbers are the natural numbers (counting numbers, 1, 2, 3...), but starting with zero instead of one. -1 is an integer but not a whole number.

5 0

3 years ago

Read 2 more answers

Juan bought 5 cupcakes and 3 bearclaws for 45$. Lily bought 4 of the same cupcakes and 6 of the same bearclaws for 72$. What is

puteri [66]

Answer:

Cup cakes= $3

Bear claws = $10

Step-by-step explanation:

Let the orice of cupcakes be x and the price of bear claws be y

5x+ 3y= 45

4x + 6y= 72

Multiply equation 1 by 4 and equation 2 by 5

20x + 12y= 180

20x + 30y= 360

-18y= -180

y= 10

Substitute 10 for y in equation 1

5x + 3(10)= 45

5x + 30= 45

5x = 45-30

5x= 15

x= 15/5

= 3

Hence the price of cup cakes is 3 and bear claws is $10

8 0

3 years ago

HELP NOW! A music club has 35 drum players. If 25% of the total number of members in the club are drum players, what is the tota

seraphim [82]

140 total members. 35 is just 1/4 of the members there so you can just multiply it 4 times to get your answer because 100% of members is 140

35 = 25%
70 = 50%
105 = 75%
140 = 100%

6 0

3 years ago

Read 2 more answers

I NEED HELP PLS THIS IS DUE IN 3 HOURS

Mariulka [41]

Answer:

Part 1) $x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2) $x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 1)

in this problem we have

$x^{2} -2x-2=0$

$a=1\\b=-2\\c=-2$

substitute in the formula

$x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}$