Υм ι тнιʝк ιтѕ 300 .нσρє ιт нєℓρѕ
Answer: Nine less than two thirds of a quantity is smaller than one more than that same quantity.
Answer:
Step-by-step explanation:
We want to determine a 90% confidence interval for the mean amount of time that teens spend online each week.
Number of sample, n = 41
Mean, u = 43.1 hours
Standard deviation, s = 5.91 hours
For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
43.1 ± 1.645 × 5.91/√41
= 43.1 ± 1.645 × 0.923
= 43.1 ± 1.52
The lower end of the confidence interval is 43.1 - 1.52 =41.58
The upper end of the confidence interval is 43.1 + 1.52 =44.62
Therefore, with 90% confidence interval, the mean amount of time that teens spend online each week is between 41.58 and 44.62
Hello :
<span>C.) (4 · 4) – (4 ÷ 4) =16-1=15</span>
5 shirts per 20 minutes
three 20 minute segments in 1 hour
5 x 3 = 15
1 hr = 15 shirts
so 15 shirts / hr! hope this helped :3
