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Shtirlitz [24]
4 years ago
7

A manager wants to build 3-sigma x-bar control limits for a process. The target value for the mean of the process is 10 units, a

nd the standard deviation of the process is 6. If samples of size 9 are to be taken, what will be the upper and lower control limits, respectively? 12 and 8 -8 and 28 4 and 16 16 and 4 8 and 12
Mathematics
1 answer:
lubasha [3.4K]4 years ago
3 0

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Mean = 10

Sample size = 9

Standard deviation = 6

We need to find the upper and lower control limits.

so, Lower limit would be

\bar{x}-3\dfrac{\sigma}{\sqrt{n}}\\\\=10-3\times \dfrac{6}{\sqrt{9}}\\\\=10-6\\\\=4

Upper limit would be

\bar{x}+3\dfrac{\sigma}{\sqrt{n}}\\\\=10+3\times \dfrac{6}{\sqrt{9}}\\\\=10+6\\\\=16

Hence, Third option is correct.

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Write the equation of the line that passes through the points (3, 6) and (5, 18) using function notation.
andreev551 [17]

Answer:

f(x) = 6x -12

Step-by-step explanation:

We must write the function of the line in the form f (x) = mx + b

First calculate the slope m

m =\frac{y_2-y_1}{x_2-x_1}

y_2 = 18\\y_1 =6\\x_2=5\\x_1=3

m= \frac{18-6}{5-3} = 6

Then

f(x) = 6x +b

To have b replaced a point in the function

f(3)=6 = 6(3) +b\\\\6-18= b\\\\b=-12

Finally the function is

f(x) = 6x -12

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3 years ago
Lucy is raising money for a school trip by selling lollipops and bags of
sukhopar [10]
<h3>16 lollipops and 9 bags of chips are sold</h3>

<em><u>Solution:</u></em>

Let "x" be the number of lollipops sold

Let "y" be the number of bags of chips sold

Cost of 1 lollipop = $ 1.50

Cost of 1 bag of chip = $ 1.75

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Therefore,

x + y = 25

y = 25 - x -------- eqn 1

<em><u>Yesterday Lucy made $39.75</u></em>

Therefore,

number of lollipops sold x Cost of 1 lollipop + number of bags of chips sold x Cost of 1 bag of chip = 39.75

x \times 1.50 + y \times 1.75 = 39.75

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<em><u>Substitute x = 16 in eqn 1</u></em>

y = 25 - 16

<h3>y = 9</h3>

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3 years ago
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Answer:

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