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REY [17]
3 years ago
12

Find the angle measure and show work. (100pts)

Mathematics
2 answers:
steposvetlana [31]3 years ago
7 0

Answer:

120 = m PR

Step-by-step explanation:

The angle formed outside =1/2(difference of intercepted arcs)

60 = 1/2 (major arc - minor arc)

60 = 1/2 (longPR - short PR)

120 = long PR - short PR

long PR = 360 - short  PR since a circle is 360 degree

120 = 360 - short  PR - short PR

120 = 360 -2 short PR

Subtract 360 from each side

120-360 =  -2 short PR

-240 =  -2 short PR

Divide by -2

120 = m PR

Maru [420]3 years ago
5 0

Answer:

m(PR) = 120°

Step-by-step explanation:

∠P+∠Q+∠R+∠O = 360° } => ∠O = 180° - 60° = 120°

∠P+∠R = 180°

∠O = m(PR) => m(PR) = 120°

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Please help asap, brainliest,thanks, and 50 points. Thank you soooo much! <3
Anuta_ua [19.1K]

Answers:

1) x^{8} y^{8}

2) y^{3} \sqrt{y}

3) 5x^{4} \sqrt{6}

4) \sqrt{7}

5) \frac{\sqrt{z}}{z}

Step-by-step explanation:

1) \sqrt{x^{16} y^{36}}

Rewriting the expression:

(x^{16} y^{36})^{\frac{1}{2}}

Multiplying the exponents:

x^{\frac{16}{2}} y^{\frac{36}{2}}

Simplifying:

x^{8} y^{8}

2) \sqrt{y^{7}}

Rewriting the expression:

\sqrt{y^{6} y}=(y^{6} y)^{\frac{1}{2}}

Multiplying the exponents:

y^{\frac{6}{2}} y^{\frac{1}{2}}

Simplifying:

y^{3} y^{\frac{1}{2}}=y^{3} \sqrt{y}

3) \sqrt{150 x^{8}}

Rewriting the expression:

\sqrt{(6)(25) x^{8}}

Since \sqrt{25}=5:

5x^{4}\sqrt{6}

4) \frac{7}{\sqrt{7}}

Multiplying numerator and denominator by \sqrt{7}:

\frac{7}{\sqrt{7}} (\frac{\sqrt{7}}{\sqrt{7}})=\frac{7}{7\sqrt{7}}

Simplifying:

\sqrt{7}

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Rewriting the expression:

\frac{5z}{5z \sqrt{z}}

Simplifying:

\frac{1}{\sqrt{z}}

Since we do not want the square root in the denominator, we can multiply numerator and denominator by \sqrt{z}:

\frac{1}{\sqrt{z}}(\frac{\sqrt{z}}{\sqrt{z}})

Finally:

\frac{\sqrt{z}}{z}

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4 years ago
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3w + 9w = 9

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Answer:

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Answer:

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