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3 years ago

Express x^2+8x+15 in the form (x+a)^2-b

Mathematics

1 answer:

IRINA_888 [86]3 years ago

7 0

Step-by-step explanation:

We have,

$x^2$ + 8x + 15

To express $x^2$ + 8x + 15 in the form of $(x+a)^2$ - b = ?

∴ $x^2$ + 8x + 15

Adding and subtracting 1, we get

= $x^2$ + 8x + 15 + 1 - 1

= $x^2$ + 8x + 16 - 1

= $x^2$ + 2(x)(4) + $4^{2}$ - 1

Using the algebraic identity,

$(x+y)^{2}=x^{2} +2xy+y^{2}$

= $(x+4)^2-1$

Thus, $(x+4)^2-1$ in the form of $(x+a)^2$ - b.

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If 8 widgets equal 4 curlicues and

dalvyx [7]

So 8w=4c and 2c=3g. divide the first equation by 2 and you get 4w=2c. merge the two equation give you 4w=2c=3g, or 4w=3g. multiply 4 on both sides give you 16w=12g. So 16 widgets equal how 12 goof-ups?

6 0

3 years ago

The perimeter of a building is 78 feet. The width of the building is seven more than three times the length of the building. Wha

Alchen [17]

P=2l+2w

W=7+3l

So substitute into the original equation

P=2l + 2(7+3l)

78=2l +14 + 6l

-14 -14

—————-

64=8l

8=length

W=7+3l

= 7+3(8)

=7+24

=31

Check your work

Perimeter=8+8+31+31

=78

Hope this helps

8 0

3 years ago

(03.02 MC)

kotykmax [81]

Answer:

The coordinates of J are missing. Plus, I don't see options for the conclusions. I made an imaginary point J, which you could correct to form the proper triangle.

Step-by-step explanation:

See the attachment. Plot all the vertices, including a corrected point J and draw the resulting triangle. It might be that AJKL is a slightly smaller, shifted version of AGHI. Enter the correct coordinates and then compare.