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vlada-n [284]
3 years ago
13

Help on number 5 please

Mathematics
1 answer:
Llana [10]3 years ago
5 0
What is the answer I can help but first what is the answer?
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50 POINTS
NeX [460]

Answer:

o I = 4 cm, w = 9 cm, h = 3 cm  

Step-by-step explanation:

The volume is given by V = l*w*h

w = 6 cm, I = 4,cm, h = 4 cm    V= 6*4*4 = 96

o w = 7 cm, h = 3 cm, I = 5 cm   V = 7*3*5 =105

o I = 4 cm, w = 9 cm, h = 3 cm   V = 4*9*3 =108

o h = 5 cm, w = 6 cm, I = 3 cm  V = 5*6*3 =90

The largest volume is

o I = 4 cm, w = 9 cm, h = 3 cm   V = 4*9*3 =108

8 0
2 years ago
Read 2 more answers
9x9=<br> 8x8=<br> 8x7=<br> 5x4=<br> Vă rog să mă ajutați
sergiy2304 [10]

Answer:

9×9=72

8×8=64

8×7=56

5×4=20

4 0
3 years ago
Read 2 more answers
. Tell whether the slope of a line that models the linear relationship is positive,
Furkat [3]
Answer:The slope of the line is both ppsitive and linear.
4 0
3 years ago
Read 2 more answers
Polynomial Equation question<br>(Screenshot included)
Illusion [34]

y = {x}^{3}  - 4 {x}^{2}  - 45x \\ y = x( {x}^{2}  - 4x - 45) \\ y = x(x + 5)(x - 9) \\ x = 0, - 5,9
So, to find our x-intercepts, y must be zero
0 = x \\  \\ 0 = (x + 5) \\  - 5 = x \\  \\ 0 = (x - 9) \\ 9 = x
ANSWER: (0,0) (-5.0) (9,0) are your x-intercepts
6 0
3 years ago
According to an​ airline, flights on a certain route are on time 80 ​% of the time. suppose 10 flights are randomly selected and
natulia [17]
<span>(a) This is a binomial experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
​(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
​(c) Fewer than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
​(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
6 0
2 years ago
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