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Licemer1 [7]
3 years ago
6

Tamara was asked to write an example. My baby-sitting service charges an initial $5.00 fee plus additional $6.50 per hour

Mathematics
1 answer:
Alona [7]3 years ago
8 0

Answer:

Step-by-step explanation:

5$ tax

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PLZ HLP ASAP WILL MARK BRIANLEIST
alisha [4.7K]
.625 
take the amount of quarts divide it by 4 we get .625 then we put it was a fraction 625/1000 after we simplify we get 5/8
5/8 of a can per quart
6 0
4 years ago
Read 2 more answers
Please help!
Mrac [35]

Answer:

Equilateral triangles are sometimes

acute triangles.

Scalene triangles are never

acute triangles.

Right triangles are never

acute triangles.

Obtuse triangles are always

isosceles triangles.

3 0
3 years ago
Kaylee put an empty cup underneath a leaking faucet. After 1 1/2 hours, Kaylee collected 1/4 cup of water. What is the rate in c
Tju [1.3M]

Answer:

I think it is 6/1

Step-by-step explanation:

You are wrong because 0.167 into a fraction is 167/1000 and that isn't one of the options but when I did it 1 1/2=3/2=1.5 and 1/4=0.25 so I did 1.5 divide by 0.25 and it gave me 6 so that why I think that my answer is correct and yours is not.

4 0
4 years ago
At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4
wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

1.

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}

2.

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\  \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}

3.

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\  \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\  \\ \therefore E_1\equiv E_2=55580ft \end{gathered}

6 0
1 year ago
Test for the commutative property of union and intersection of the sets P = { x : x is all real numbers between 2 and 7} and Q =
In-s [12.5K]

Answer:

Step-by-step explanation:

P = {x : x is a real number between 2 and 7}

{x: 3,4,5,6}

Q = {x : x is all rational number between 2 and 7}

{4 }

We know that P contains all the rational numbers between 2 and 7.

And P ∪ Q and Q ∪ P each of them contain all the real numbers which are between 2 and 7.

{3,4,5,6}

Here Q is the proper subset of P

P ∩ Q = Q ∩ P = Q= {4}

4 0
3 years ago
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