What transformations occur on the absolute value function for -4f(x+2)-5?

The population of the Wallingfried neighborhood has been growing steadily since 1981. In 1985, the population was 28000 people.

NeX [460]

Answer:

This answer has been deleted by the user.

Step-by-step explanation:

8 0

4 years ago

What is 0.118 in expanded form

antoniya [11.8K]

Answer:

zero and one-hundred eighteen-thousandths

4 0

4 years ago

A university's housing and residence office wants to know how much students pay per month for rent in off-campus housing. The un

Shkiper50 [21]

Answer:

a) For this case the population of study is " the 12,304 students who live in off-campus housing and have not yet graduated " since the objective of the study is know how much students pay per month for rent in off-campus housing. So thn th epopulation size is N = 12304.

b) They select 200 students who live in off-campus housing and have not yet graduated selected using random sampling from the total population of 12304. So the sample size is n=200

As we can see in the info they got response just for 78 questionairres, so then the response rate is (78/200)*100 =39% and the non response rate is 100-39= 61.

So at the end the final sample consist on 39% of the original sample with 78 responses available for the analysis.

For this case we can redefine the sample as "The k students selected at random who live in off-campus housing and have not yet graduated and answer the mail questionairries ". And as we can see we have a better definition fo the real sample for this situation.

Step-by-step explanation:

Previous concepts

The term population represent to the total set of observations in a sample space S defined, and with an specified characteristics.

The term sample represent a set of individuals or objects who are a subsample of the population who are "collected or selected from a statistical population by a defined procedure".

Part a

For this case the population of study is " the 12,304 students who live in off-campus housing and have not yet graduated " since the objective of the study is know how much students pay per month for rent in off-campus housing. So thn th epopulation size is N = 12304.

Part b

They select 200 students who live in off-campus housing and have not yet graduated selected using random sampling from the total population of 12304. So the sample size is n=200

As we can see in the info they got response just for 78 questionairres, so then the response rate is (78/200)*100 =39% and the non response rate is 100-39= 61.

So at the end the final sample consist on 39% of the original sample with 78 responses available for the analysis.

For this case we can redefine the sample as "The k students selected at random who live in off-campus housing and have not yet graduated and answer the mail questionairries ". And as we can see we have a better definition fo the real sample for this situation.

3 0

3 years ago

(1-sinx+cosx)^2 = 2(1+sinx)(1+cosx)

bogdanovich [222]

If you're trying to establish an identity, the given equation is not an identity. The proper identity would be as follows:

(1 - sin(x) + cos(x))² = (1 - sin(x))² + 2 (1 - sin(x)) cos(x) + cos²(x)

… = (1 - 2 sin(x) + sin²(x)) + 2 (1 - sin(x)) cos(x) + cos²(x)

… = 2 - 2 sin(x) + 2 (1 - sin(x)) cos(x)

… = 2 - 2 sin(x) + 2 cos(x) - 2 sin(x) cos(x)

… = 2 (1 - sin(x) + cos(x) - sin(x) cos(x))

… = 2 (1 - sin(x) + cos(x) (1 - sin(x)))

… = 2 (1 - sin(x)) (1 + cos(x))

But if you're trying to solve an equation:

(1 - sin(x) + cos(x))² = 2 (1 + sin(x)) (1 + cos(x))

2 (1 - sin(x)) (1 + cos(x)) = 2 (1 + sin(x)) (1 + cos(x))

(1 - sin(x)) (1 + cos(x)) - (1 + sin(x)) (1 + cos(x)) = 0

(1 + cos(x)) (1 - sin(x) - 1 - sin(x)) = 0

-2 sin(x) (1 + cos(x)) = 0

sin(x) = 0 or 1 + cos(x) = 0

sin(x) = 0 or cos(x) = -1

[x = arcsin(0) + 2nπ or x = arcsin(0) + π + 2nπ] or

… [x = arccos(-1) + 2nπ]

We have arcsin(0) = 0 and arccos(-1) = π, so the solution set reduces to

x = 2nπ or x = (2n + 1)π

(where n is any integer)

7 0

3 years ago

In the lottery every week, 2,000,000 tickets are sold for $1 apiece. Say 4000 of these tickets pay off $30 each, 500 pay off $80

jarptica [38.1K]

The expected value is just the weighted average of how much one ticket wins. To calculate it, we need to find the probabilities of winning each dollar amount, multiply each probability with it's respective dollar amount, then find the sum.

Let's call the winnings from one ticket X:

P(X=30) = 4000/2000000 = 0.002

P(X=800) = 500/2000000 = 0.00025

P(X=1200000) = 1/2000000 = 0.0000005

E(X) = 30*P(X=30) + 800*P(X=800) + 1200000*P(X=1200000) = 0.06 + 0.2 + 0.6 = 0.86

The answer is $0.86

4 0

4 years ago