Answer:
![m = \frac{4}{7}\\](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B4%7D%7B7%7D%5C%5C)
Step-by-step explanation:
Given
The attached graph
Required
The constant rate of change (m)
This is calculated as:
![m = \frac{y_2 -y_1}{x_2 - x_1}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_2%20-y_1%7D%7Bx_2%20-%20x_1%7D)
From the graph, we have:
![(x_1,y_1) = (3,4)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%20%3D%20%283%2C4%29)
![(x_2,y_2) = (10,8)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29%20%3D%20%2810%2C8%29)
So, the formula becomes:
![m = \frac{8-4}{10 - 3}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B8-4%7D%7B10%20-%203%7D)
![m = \frac{4}{7}\\](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B4%7D%7B7%7D%5C%5C)
Answer:
The answer is they are all correct
Step-by-step explanation:
5 +3(1) = 8 = 3(1)+5
5 +3(2) = 11 = 3(2)+5
5 +3(3) = 14 = 3(3)+5
5 +3(4) = 17 = 3(4)+5
5 +3(5) = 20 = 3(5)+5
Answer:
D. 7n+35
Step-by-step explanation:
The two rational expressions will be; (x + 2)/(x² - 36) and 1/(x² + 6x)
<h3>How to simplify Quadratic Expressions?</h3>
We want to determine the two rational expressions whose difference completes the equation.
The two rational expressions will be;
(x + 2)/(x² - 36) and 1/(x² + 6x)
Now, this can be proved as follows;
Step 2 [(x + 2)/(x² - 36)] - [1/(x² + 6)]
= [(x + 2)/(x + 6)(x - 6)] - [1/(x(x + 6)]
Step 3; By subtracting, we have;
[x(x + 2) - (x - 6)]/[x(x + 6)(x - 6)]
Step 4; By further simplification of step 3, we have;
[x² + x + 6]/[x(x-6)(x + 6)]
Read more about Quadratic Expressions at; brainly.com/question/1214333
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Answer:
Yes, you can make a triangle with it
Step-by-step explanation:
Given
![Lengths: 9in, 4in, 6in](https://tex.z-dn.net/?f=Lengths%3A%209in%2C%204in%2C%206in)
Required
Do the lengths form a valid triangle
To do this, we make use of triangle inequality theorem which states that;
For sides a, b and c;
![a + b > c](https://tex.z-dn.net/?f=a%20%2B%20b%20%3E%20c)
![b + c >a](https://tex.z-dn.net/?f=b%20%2B%20c%20%3Ea)
![a + c > b](https://tex.z-dn.net/?f=a%20%2B%20c%20%3E%20b)
So, we have:
-- true
-- true
-- true
<em>Since all the inequalities are true, then the sides form a valid triangle</em>