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Dmitrij [34]
3 years ago
15

A box has a volume of 144 in3 and a height of 4 1/2 in.What is the base area of the box?

Mathematics
1 answer:
Zepler [3.9K]3 years ago
8 0

Box volume can be computed by getting the base area multiplied by the total height.

in formula for volume we have,

V = Base Area x H. Given the Volume of 144 cu in and H = 4.5 in. we can solve for Base Area (BA)

Volume (144 cu in) = BA x Height (4.5 in)

BA = 144 cu in/4.5 in

Base Area = 32 square inches

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The squirrel could store 48 nuts in a hiding place. If there were 768 nuts to hide, how
Dmitrij [34]

Answer:

16 hiding places

Step-by-step explanation:

768/48

=16

nuts hided/storing the nuts

7 0
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Read 2 more answers
Write 5 pounds for $2.49 a unit rate round to the nearest hundredth
slava [35]

About $0.50 per pound.

3 0
3 years ago
Casey knit a square shaped dish cloth. What is the area of the dishcloth?
tester [92]
Take the length of one side and multiply it by itself and that will be your answer

6 0
3 years ago
The accompanying data represent the daily​ (for example, Monday to​ Tuesday) movement of Johnson​ & Johnson​ (JNJ) stock for
egoroff_w [7]

Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

  • The lower bound is of 0.484.
  • The upper bound is of 0.7292.
  • The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

Supposing that it increases on 37 out of 61 days:

n = 61, \pi = \frac{37}{61} = 0.6066

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292

The ​95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

A similar problem is given at brainly.com/question/16807970

4 0
2 years ago
How do we solve for x
blondinia [14]
X/2 + 5 = -10
x/2 = -10 - 5
x/2 = -15
x = -15(2)
x = -30
3 0
3 years ago
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