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zubka84 [21]
4 years ago
7

SUPER EASY WILL UPVOTE Create a number sequence in which the first term is 4. Explain the pattern that you used.

Mathematics
1 answer:
Darya [45]4 years ago
7 0
The sequence is 4, 5, 6, 7, 8, ..... The pattern is: Each term is (the term before it) plus (1).
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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Darina [25.2K]

Answer:

Given definite  integral as a limit of Riemann sums is:

\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Step-by-step explanation:

Given definite integral is:

\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}

Substituting (2) in above

f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Riemann sum is:

= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

4 0
4 years ago
Jessica bought a soft drink for 2 dollars and 6 candy bars. She spent a total of 20 dollars. How much did each candy bar cost!
liq [111]

Answer:

4 dollars

Step-by-step explanation:

i subtracted the total money spend from the soft drink

18$ - 2$ = 16$ was spent in buying the candy bars

and she bought 4 candy bars so  we divide 16$ by 4 = 4$ for each candy bars

7 0
3 years ago
!!!!!!!!!!!!!!!!!!!!!
Aleonysh [2.5K]

Answer:

He would run a half of a lap because if he ran a full lap in 2 minutes than in 1 minute it would be half of 1.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How can you use place value and partial products to multiply 2-digit number?
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By multiplying answers separately then the products are then added together. like: 182
x. 6
600
480 partial product
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7 0
4 years ago
Help meeee please ydyeyr
iogann1982 [59]

Answer:

Below

Step-by-step explanation:

Shane

25=1 car

50=2 cars

75=3 cars

100=4 cars

125=5 cars

Lucas

30=1 car

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