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3 years ago

Solve x3 + 4x2 – x – 4 = 0

Mathematics

1 answer:

Sauron [17]3 years ago

4 0

I think it is x ∈ { −4, −1, 1}<span>
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Type the correct answer in the box. Assume that pi=3.14 and round your answer to the nearest integer.

stepan [7]

Answer:

$648\ yd$

Step-by-step explanation:

step 1

Find the circumference of the complete circle

The circumference is equal to

$C=2\pi r$

we have

$r=35\ yd$

substitute

$C=2\pi(35)$

$C=70\pi\ yd$

step 2

Find the measure of the arc length for a central angle of 280 degrees

Remember that the circumference subtends a central angle of 360 degrees

so by proportion

$\frac{70\pi}{360}=\frac{x}{280}\\ \\x=280*(70\pi )/360\\ \\x=54.44\pi\ yd$

step 3

Find the perimeter of the playground

$P=54.44\pi+45=54.44*3.14+45=215.96\ yd$

Multiply by 3

$215.96*(3)=647.87\ yd$

Round to the nearest integer

$647.87=648\ yd$

7 0

3 years ago

Read 2 more answers

Convert 3,450,000 into scientific notation.

Levart [38]

Answer:

3.45 x 106

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the circumference of these circles

EastWind [94]

Formula for Circumference is 2*Pi*radius

1. 18.84 in.
2. 56.52 cm
3. 4.71 ft
4. 25.12 m
5. 37.68 ft.
6. 12.56 yd.
7. 43.96 in
8. 28.26 cm
9. 7.85 m

4 0

3 years ago

Write the numbers from least to greatest. 0.66 -1/3 -5/12

SpyIntel [72]

The answer is -1/3, -5/12, 0.66

5 0

3 years ago

Read 2 more answers

A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?

alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is $\frac{1}{13}$ .

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is $4\times 51!$ .

The probability that the last card dealt is an ace is

$P=\frac{4\times 51!}{52!}$

$P=\frac{4\times 51!}{52\times 51!}$

$P=\frac{4}{52}$

$P=\frac{1}{13}$

Therefore, the probability that the last card dealt is an ace is $\frac{1}{13}$ .

4 0

3 years ago