X⁴-14x²+45=0
(x²) ²-14x²+45=0
let y=x²
y²-14y+45=0
(y-9) (y-5) =0
y=9 or y=5
x²=9 or x²=5
x=±3 or x=±√5
X<-7 so the answer would be greater*
Answer:
C' (-4 , 2)
slope of new line = line "L" = -2
Step-by-step explanation:
C (x₀,y₀): (0,2) dilation center (h,k): (2,2) scale factor (sf): 3
C' (x,y)
x = 2 + 3*(0-2) = -4 x = h + sf*(x₀ - h)
y = 2 + 3*(2-2) = 2 y = k + sf*(y₀ - k)
C' (-4 , 2)
slope of new line = line "L" = -2