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Veronika [31]
3 years ago
8

Hi, I'm offering a lot of points you can't find my answer online you have to actually do math. I'd like to see the equation just

to see it makes sense because Brainly unfortunately gives me trust issues with all the wrong answers because no one uses there brain on here only "let's try to find it online just to get points" so anyways please can you help with this garbage equation that's probably super simple but I'm an idiot...
Max is building a scale model of the solar system. In Max's model, the distance from Earth to the sun is 1.2 feet, and the distance from Venus to the sun is 0.86 feet.

If the approximate distance from Earth to the sun is 93 million miles, what is the approximate distance from Venus to the sun?

(And remember If possible I'd like to see the equation. :) ) thanks very much.
Mathematics
2 answers:
tatuchka [14]3 years ago
5 0

Answer:

66.65 million miles

Step-by-step explanation:

In Max's model, the distance from Earth to the sun is 1.2 feet, which represents 93 million miles

so the distance from Venus to the sun is 0.86 feet which represents

93 million miles/1.2*0.86 = 66.65 million miles

Nataly_w [17]3 years ago
4 0
So, to find the constant we do this:
1.2n = 93,000,000
so n = 77500000So, with this constant, we multiply n with 0.86
0.86n = <span>66650000
So Venus is about </span><span>66,650,000 million miles away from the sun</span>
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38/58 in it's simplest form
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19/29

Find the common factor which in this case is 2. Divide numerator and denominator by common factor. You’re left with 19/29. Since 19 and 29 don’t have any common factors it is in its simplest form.
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3 years ago
Five books cost¢21. what is the price cost of seven similar books​
Liono4ka [1.6K]

Answer:

Your answer should be $29.40

Step-by-step explanation:

If you divide 21 by 5 you get 4.2, so each book costs $4.20.

4.2 x 7 = 29.4

Therefore, your total cost for 7 books will be $29.40

I hope this helps!

5 0
3 years ago
What is the following expression when simplified 5x + 8(5 + 2x)?
denpristay [2]

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6 0
3 years ago
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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
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