Answer:
-1
Step-by-step explanation:
Formula to the determinant is:
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20ad-bc)
0(0)–1(1)
0-1
-1
We know that y is equal to x-2. We can just substitute x-2 for y since y is equal to it.
10x- 9(x-2)=24
Distribute.
10x- 9x+18= 24
x+18= 24
Subtract 18 on both sides.
x= 6
Now, plug in x.
y= (6)-2
y= 4
We can check this to see if this works:
4= 6-2, 4=4
10(6)- 9(4)= 24
60-36= 24, 24=24
x=6 and y=4
I hope this helps!
<em>~kaikers</em>
For this case we have the following vectors:

The dot product of two vectors is a scalar.
The point product consists of multiplying component by component and then adding the result of the multiplication of each component.
For the product point of the vectors a and b we have:
Answer:
The product point of the vectors a and b is:
Answer:
is it fighet spinner or I am wrong hahahaa fighet spinner