3 years ago

Simplify the expression below 5x(2x - 5)

Mathematics

1 answer:

GenaCL600 [577]3 years ago

7 0

First you do (2x-5) witch is -3x
Then you 5x times -3x and it will be 12x

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URGENT! find the sum. the answer is not D

otez555 [7]

<h3>Answer: C) -1/2</h3>

=============================================

Explanation:

We'll apply the derivative to get

g(x) = 4x^3 + 3x^2

g ' (x) = 3*4x^2 + 2*3x

g ' (x) = 12x^2 + 6x

Set that equal to 0 and solve for x. We do this to find where the horizontal tangents are located.

g ' (x) = 0

12x^2 + 6x = 0

6x(2x + 1) = 0

6x = 0 or 2x+1 = 0

x = 0 or x = -1/2

Adding those two said solutions yields us the final answer choice C

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

I am working on a test review. How can I write -1 <= 2x+7 <21 as two inequality statements? How do I join them with and/or

Tanya [424]

Answer:

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3 years ago

Tank a has a capacity of 9.5 gallons. 6 1/3 gallons of the tank's water are poured out. how many gallons of water are left in th

Advocard [28]

Answer:

Water left in tank is $3\frac{1}{6}$ gallons.

Step-by-step explanation:

Given :

Capacity of tank = 9.5 gallons $=\frac{95}{10}$

Water taken out of tank = $6\frac{1}{3}=\frac{19}{3}$ gallons

We have to find the water left in the tank.

Water left in the tank = Total capacity of tank - water taken out of tank

= $\frac{95}{10}-\frac{19}{3}$

Taking LCM of (3,10)= 30

$\Rightarrow \frac{95 \times 3-19 \times10}{30}$

Solving further, we get,

$\Rightarrow \frac{285-190}{30}$

$\Rightarrow \frac{95}{30}=\frac{19}{6}=3\frac{1}{6}$

Thus, Water left in tank is $3\frac{1}{6}$ gallons..

5 0

3 years ago

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