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RSB [31]
3 years ago
13

Here is a picture of a cube, and the net of this cube.

Mathematics
2 answers:
Irina-Kira [14]3 years ago
5 0

Answer: 864\text{ mm}^2

Step-by-step explanation:

Given: the side length of the cube = 12mm

The surface area of the cube is given by :-

\text{Surface area }=6(side)^2

Therefore, the surface area of the given cube will be :-

\text{Surface area }=6(12)^2=6\times144=864\text{ mm}^2

hence, the surface rae of the cube is 864\text{ mm}^2

stich3 [128]3 years ago
4 0
SA= 6s^2 (s= side length)
= 6(12)^2
=864 mm
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Answer:


Step-by-step explanation:

The power of a power rule is when power is raised to another power. (x^n)^m.  when you do this rule, you must multiply the exponents so, x^nm or x^n*m.

The product rule for exponents is used when there are multiple terms that are raised by an exponent that have the same base and ae being multiplied. x^3 * x^2. To solve this, you keep the base (x) and add the two exponents together (3 and 2) so, x^3+2 = x^5.

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A rock sample containing an isotope with a half-life of 28 million years has an initial mass of 184 grams. how much time has ela
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<h2>Half Life</h2>

The half life period is the time in which only half of the given population remains. It can be represented through this equation:

f(t)=a\times(1/2)^{\frac{t}{h}}

  • <em>t</em> = time passed
  • <em>a</em> = y-intercept
  • <em>h</em> = half life

<h2>Solving the Question</h2>

We're given:

  • <em>h</em> = 28 million years
  • <em>a</em> = 184 grams (this is the initial mass, after 0 time has passed)

For most questions like this, we would have to plug these values into the equation mentioned above. However, this question asks for the time elapsed after 3 half-lives.

This can be calculated simply by multiplying the given half-life by 3:

28 million years x 3

= 84 million years

<h2>Answer</h2>

84 million years

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