All categories

1 year ago

What are the domain and range of the exponential function below?

Mathematics

1 answer:

Hunter-Best [27]1 year ago

3 0

The domain and the range of the function are all set of real numbers

<h3>How to determine the domain and the range?</h3>

The function is given as:

f(x) = 4x + 3

The above function is a linear function

Linear functions have a domain and a range of all set of real numbers

Hence, the domain and the range of the function are all set of real numbers

Read more about domain and range at:

brainly.com/question/1632425

#SPJ1

You might be interested in

F(x)=2x+3 find x=9 explain how you got the answer please help me I need the answer today

hram777 [196]

You would fill in 9 for x so your equation would be 2(9)+3 and you would then get 21. Therefore the answer is f(x)=21

6 0

3 years ago

Sutopa has 3/4 of the money Maneet has. Maneet has $18 less than Kim. Together, they have $286.40. How much money does each of t

anastassius [24]

Solving a system of equations we can see:

Sutopa has $73.20
Maneet has $97.60
Kim has $115.60

<h3>How much money each of them has?</h3>

First, let's define the variables:

S = money that Sutopa has.
M = money that Maneet has.
K = money that Kim has.

We can write the system of equations:

S = (3/4)*M

M = K - $18

S + M + K = $286.40

First, we can rewrite the second equation to get:

K = M + $18

Now we can replace the first and second equations into the third one:

(3/4)*M + M + (M + $18) = $286.40

Now we can solve this for M:

M*(1 + 1 + 3/4) = $286.40 - $18

M = $268.40*(4/11) = $97.60

Now we can find the other two values:

K = M + $18 = $97.60 + $18 = $115.60

S = (3/4)*M = (3/4)*$97.60 = $73.20

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

6 0

2 years ago

Complete the square to rewrite the equation in the form (x−h)2=p.

soldier1979 [14.2K]

Answer:

second option

Step-by-step explanation:

Given

x² - 6x - 33 = 0 ( add 33 to both sides )

x² - 6x = 33

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 3)x + 9 = 33 + 9

(x - 3)² = 42 → second option

4 0

3 years ago

How to solve this trig

n200080 [17]

Hi there!

To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).

First Question

What we have to do is to isolate cos first.

$\displaystyle \large{ cos \theta = - \frac{1}{2} }$

Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.

Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.

Find Q2

$\displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }$

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }$

Both values are apart of the interval. Hence,

$\displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }$

Second Question

Isolate sin(4 theta).

$\displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }$

Rationalize the denominator.

$\displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }$

The problem here is 4 beside theta. What we are going to do is to expand the interval.

$\displaystyle \large{0 \leqslant \theta < 2 \pi}$

Multiply whole by 4.

$\displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}$

Then find the reference angle.

We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.

sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }$

Find Q4

$\displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }$

Both values are in [0,2π). However, we exceed our interval to < 8π.

We will be using these following:-

$\displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}$

Hence:-

For Q3

$\displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }$

We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.

For Q4

$\displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }$

Therefore:-

$\displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }$

Then we divide all these values by 4.

$\displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }$

Let me know if you have any questions!

3 0

2 years ago

If w = 10 units, x= 5 units, and y= 6 units, what is the surface area of the figure?

qwelly [4]

Answer:

456.2 units²

Step-by-step explanation:

The area of the square base is ...

base area = w² = (10 units)² = 100 units²

The lateral area is 4 times the area of one rectangular face:

lateral area = 4wx = 4(10 units)(5 units) = 200 units²

The area of one triangular face is half the product of its base length (w) and its slant height (h). The latter is found using the Pythagorean theorem:

h² = y² +(w/2)² = (6 units)² +((10 units)/2)² = 61 units²

h = √61 units

So, the area of 4 triangles is ...

area of triangular faces = 4(1/2)wh = 2(10 units)(√61 units) ≈ 156.2 units²

Now we have the areas of the parts, so we can add them together to get the total surface area:

surface area = base area + lateral area + area of triangular faces

= 100 units² + 200 units² + 156.2 units²

surface area = 456.2 units²

4 0

3 years ago