Question

What would be the sum of the lengths of the first and second diagonals rounded to the nearest whole number?

Answer 1

Answer:

16.17684994

Step-by-step explanation:

First diagonal

x^2 = a^2 + b^2

x^2 = 5^2 + 6^2

x^2 = 61

x ≈ 7.810249676

Second diagonal

x^2 = a^2 + b^2

x^2 = 7.810249676^2 + 3^2

x^2 = 70

x ≈ 8.366600265

Sum of both diagonals

8.366600265 + 7.810249676

= 16.17684994