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Levart [38]
3 years ago
10

What would be the sum of the lengths of the first and second diagonals rounded to the nearest whole number?

Mathematics
1 answer:
drek231 [11]3 years ago
6 0

Answer:

16.17684994

Step-by-step explanation:

First diagonal

x^2 = a^2 + b^2

x^2 = 5^2 + 6^2

x^2 = 61

x ≈ 7.810249676

Second diagonal

x^2 = a^2 + b^2

x^2 = 7.810249676^2 + 3^2

x^2 = 70

x ≈ 8.366600265

Sum of both diagonals

8.366600265 + 7.810249676

= 16.17684994

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Answer:

45°

Step-by-step explanation:

Because every angle in a square is 90° and the diagonal is bisecting the angle so we have 45°

5 0
3 years ago
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Diano4ka-milaya [45]

Answer:

x = 7.416666667

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= 2 - 4
jekas [21]

Answer:

Please find attached the required inverse of a function chart

Step-by-step explanation:

The inverse of a function is found by reversing the operations of the  function

The inverse of the function f(x) = 2·x - 4 is found as follows;

x = 2·x - 4

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The inverse function is plotted by generating data points as follows;

{}x         {}          f(x)

0                2

1                  2.5

2                 3

3                  3.5

4                   4

5                   4.5

6                   5

7                   5.5

8                   6

9                   6.5

10                  7

11 {}                   7.5

12{}                    8

13                 8.5

14                  9

15                  9.5

16               10

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3 years ago
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Have a great day! =)
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25 POINTS HURRY Brainliest!!!
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I think the answer is B
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