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Alenkinab [10]
3 years ago
13

I need number 1 please and thank you

Mathematics
1 answer:
belka [17]3 years ago
4 0

Answer:

It is the third one because of formula I² + 2I*II + II²

In your case I = 4x and II = 3

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Find the mean of the data set 31,31,22,28,23?
Lina20 [59]
The mean is 27 
How you do this is you add all the numbers together even the ones that are duplicated like in this case 31. Now add em all up which equals 135. Now you take the number that they equal up to and divide by how many numbers are in the set of data in this case it is 5. After dividing you get 27.
I hope this helps!
3 0
3 years ago
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Consider the polar curve r = 4sin(2θ). What is the length of each petal, and how many petals does the graph have? a The length o
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Answer:

d The length of each petal is 4, and the number of petals is 4.

Step-by-step explanation:

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2 years ago
Evaluate the expression for the given value of the variable <br> 3a+4b; a= -6, b=-5
Dimas [21]
3 x -6 + 4 x -5
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3 years ago
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a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
Two classes have a total of 60 students. The students need to make teams of 8t
Step2247 [10]

Answer:

We have 7 complete teams

Step-by-step explanation:

Here, we have students preparing to make a team of 8 students per team. We now want to know how many complete teams they can make if they are a total of 60;

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So breaking it in 8s, we have;

8 8 8 8 8 8 8

We have 7 8s;

So there would be four left overs

3 0
3 years ago
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