B = 2 + 2H
A = 20 ft^2
H = H
Since the Area of a Triangle is Base * Height then the formula should be:
A = BH
20 = H(2+2H)
20 = 2H^2 + 2H
0 = 2H^2 + 2H - 20
Find the zeros of the quadratic equation through substituting the values of a,b, and c. You will get the zeros of x = 2.7 and -3.7. The only thing that would make sense is you use the x=2.7 because there are no negative heights.
Since b = 2h+2
b= 2(2.7) + 2
b= 5.4 + 2
b=7.4
I don't know where you got 4 and 10, but what I got is different.
To find the area of a triangle, use 1/2 x b x h. 3 x 4 = 12 1/2 of 12 = 6
There are two triangles, each of these are 6 6 x 2 = 12
The bottom shape is 3.5 x 3 3.5 x 3 = 10.5
The front shape is 3.5 x 5 3.5 x 5 = 17.5
The back shape is 3.5 x 4 3.5 x 4 = 14
Add them all together: 14 + 17.5 + 10.5 + 12 = 54
Your answer is 54!
Answer:
B
Step-by-step explanation:
Let's arrange the data set in increasing order.
We have 19, 27, 27, 33, 45, 53. The median is (27 + 33) / 2 = 30.
The new set is 19, 27, 27, 33, 45, 53, 90. The new median is 33.
Since 33 - 30 = 3 the answer is B.