Taking point (0,-2) of graph one and replacing in the equation;
2x+3y=6
2(0)+3(-2)=6
-6=6
So graph isn't the required graph.
Taking point (0,2) of graph 2;
2x+3y=6
2(0)+3(2)=6
6=6
So, graph 2 is the required graph.
The answer to that problem si 6-25+2x
Answer:
On the left because their both positive and the other one is not and also the left one is on the left y axil