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Goryan [66]
4 years ago
12

Evaluate the expression. Drag the answer into the box to match the expression. 3⋅(6^12/6^10)

Mathematics
2 answers:
fredd [130]4 years ago
6 0

\bf ~\hspace{7em}\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
3\cdot \left( \cfrac{6^{12}}{6^{10}} \right)\implies 3\cdot (6^{12}\cdot 6^{-10})\implies 3\cdot (6^{12-10})\implies 3(6^2)
\\\\\\
3\cdot 36\implies 108

Elden [556K]4 years ago
4 0

I took the test, the right answer is 108

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Answer:

2 and 2/3

Step-by-step explanation:

To multiply fractions, all you have to do is multiply the numerators by the denominators and/or simplify opposite sides.

4/9 * 6 would be 4/9 * 6/1, which equals 4/3 * 2/1. 4*2 is 8 and 3*1 is 3, so the answer would be 8/3, which simplifies to 2 2/3.

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3 years ago
Assume that adults have IQ scores that are normally distributed with a mean of mu equals 100μ=100 and a standard deviation sigma
Ksivusya [100]

Answer:

51.60% probability that a randomly selected adult has an IQ between 86 and 114.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 114, \sigma = 86

Find the probability that a randomly selected adult has an IQ between 86 and 114.

Pvalue of Z when X = 114 subtracted by the pvalue of Z when X = 86. So

X = 114

Z = \frac{X - \mu}{\sigma}

Z = \frac{114 - 100}{20}

Z = 0.7

Z = 0.7 has a pvalue of 0.7580

X = 86

Z = \frac{X - \mu}{\sigma}

Z = \frac{86 - 100}{20}

Z = -0.7

Z = -0.7 has a pvalue of 0.2420

0.7580 - 0.2420 = 0.5160

51.60% probability that a randomly selected adult has an IQ between 86 and 114.

3 0
4 years ago
The Percent of increase
ANEK [815]
Percent of Increase = Increase / Original    * 100%

Increase = $33 - $30 = $3
Original Price = $30

Percent Increase = $3 / $30  * 100%  ====  10%
5 0
3 years ago
Read 2 more answers
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