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3 years ago

Solve the equation. 4x2 – 8 = 56 2, –2 16, –16 8, –8 4, –4

Mathematics

2 answers:

Marta_Voda [28]3 years ago

6 0

Answer:

8,-8

Step-by-step explanation:

jok3333 [9.3K]3 years ago

5 0

Answer:

4,-4

Step-by-step explanation:

4x2-8=56 is our equation.

First we add 8 on both sides to get rid of the "-8" on our equation,we do it on both sides because when you do something on one side of an equation you have to do it on the other.
That will leave us with: 4x2=64
So we will solve our exponent: 4x2
Then we will have: 16x=64 because 4 times 4 is 16
Then we will divide by 16 on both sides to get rid of "16" in "16x"
That will leave us with: x=4 for our answer! :>
I hope this helped.
And please give me brainliest.
I am trying to get more brainliest.
Thank you!

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Help me with 3, and 5 show your work !

ss7ja [257]

Okay so for number 3, you have to do the top work first.

3: POSITIVE 2!! first, you do the stuff inside the parentheses first because of P(parentheses)EMDAS. so, 14-2-10! -2-10 is -12 and then plus positive 14 is +2. but, the negative sign outside of the parentheses makes that +2 a -2.
but, you cant forget the -12 outside. you have to do -12-2 which gets you -14. then, this is easy! -14 divided by -7 is a positive 2!

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3 years ago

1790.6204<br> 18.5376<br> what is the expanded notation?

Neporo4naja [7]

Answer:

1790.06204 = 1 × 1000 + 7 × 100 + 9 × 10 + 0.6204

18.5376= 1 × 10 + 8 + 0.5376

5 0

3 years ago

A box with no top is to be constructed from a piece of cardboard whose length measures 88 in. more than its width. the box is to

MariettaO [177]

Let x be the width of the cardboard (which means the length of the cardboard is x+88), then the dimensions of the box are:

Length = [(x + 88) - 2(33)]

Width = x - 2(33)

Heighth = 33

Volume = length · width · heighth

144,144 = [(x + 88) - 2(33)] · [x - 2(33)] · 33

144,144 = (x+22)(x-66)(33)

4368 = (x+22)(x-66)

4368 = x² - 44x - 1452

0 = x² - 44x - 5820

use the quadratic formula to calculate that x = 101

Answer: cardboard width = 101, cardboard length = 189

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3 years ago

I need help finding missing angles

Citrus2011 [14]

Answer:

1 = 128 degrees

2 = 52 degrees

3 = 47 degrees

4 = 133 degrees

5 = 81 degrees

Step-by-step explanation:

angle 2 and 52 degrees are corresponding angles so they are equal.

angle 3 and 47 degrees are corresponding angles so they are equal.

angles 1 and 2 are supplementary angles so their sum is 180 degrees.

angles 3 and 4 are supplementary angles so their sum is 180 degrees.

angle 5 = 180 - 52 - 47 = 81 degrees

8 0

3 years ago

Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$tan(\alpha)=cot(\beta)$

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

$csc(\beta)=\frac{7}{\sqrt{33}}$

6 0

3 years ago