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2 years ago

What is the slope intercept equation for thus line?

Mathematics

2 answers:

sveticcg [70]2 years ago

6 0

Answer:

y= 2/3 x + 4

y- intercept= (0,4)

and slope of the line is 2/3

harkovskaia [24]2 years ago

5 0

Answer:

Step-by-step explanation:

y = mx + b

The y-intercept is the point (0, 4), so you get b = 4

You now have

y = mx + 4

Now start at the y-intercept, (0, 4). Go up 2 units and right 3 units to a point on the line; rise = 2; run = 2.

slope = m = rise/run = 2/3

Now you have

y = 2/3 x + 4

Answer: B.

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Lim t^4 - 6 / 2t^2 - 3t + 7

Harman [31]

I think you meant to say

$\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}$

(as opposed to x approaching 2)

Since both the numerator and denominator are continuous at t = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}$

Because these expressions are continuous at t = 2, we can compute the limits by evaluating the limands directly at 2:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}$

6 0

2 years ago

HELP ME PLEASE 10 points!!!!!

atroni [7]

Answer:

x>9

Step-by-step explanation:

Tamika already has $55, which will stay the same independent of how much time passes. Since she deposits $5 per week, we can assign weeks a variable x. The amount of money in her account after x weeks is equal to 55+5x. If she must save over $100, we can create an inequality to solve for how many weeks must pass: 55+5x>100.

The question also asks to solve the inequality:

55+5x>100
5x>100-55 (Subtract 55 from each side)
5x>45
x>9 (Divide each side by 5)

This solution tells us that Tamika must save for more than nine weeks to have more than $100 in her account.

lmk if i made an error, hope this helps!!

3 0

1 year ago

subset to real numbers, and as you can see are not at all connected to the rest of numbers (and integers).

Natali5045456 [20]

Irrational numbers are the subset of real numbers that are not at all connected to the rest of numbers.

The subsets of real numbers are natural numbers, whole numbers, integers, rational numbers and irrational numbers.

Natural numbers are subset of whole numbers, which are subset of integers, which are subset of rational numbers. Hence, all of them are interconnected. The set of irrational numbers is the only subset of real numbers which is not associated with the rest.

For example:-

1 is a natural number, whole number, integer, rational number but not irrational number. On the other hand, $\sqrt{2}$ is an irrational number but none of the rest.