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Dominik [7]
3 years ago
9

The perimeter of a rectangle is 24 feet. The length is 3 feet less than twice the width. Which of the following systems would be

used to solve this problem ???

Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0
Alright, since the perimeter, by definition, is 2l+2w=24 in this case, we have to have that. In addition twice the width=2*width=2w, so 2w-3=l.
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podryga [215]

For this case we have the following fractions:

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C. \frac {20} {- 5} = - 4

D. \frac {-20} {5} = - 4

E .- \frac {20} {5} = - 4

As noted, the last four fractions result in -4. So, they are equivalent fractions.

Answer:

Option B, C, D, E. They are equivalent fractions.

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3 years ago
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3 years ago
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So let's put it this way-
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