The perimeter of a rectangle is 24 feet. The length is 3 feet less than twice the width. Which of the following systems would be
used to solve this problem ???
1 answer:
Alright, since the perimeter, by definition, is 2l+2w=24 in this case, we have to have that. In addition twice the width=2*width=2w, so 2w-3=l.
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