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Dominik [7]
3 years ago
9

The perimeter of a rectangle is 24 feet. The length is 3 feet less than twice the width. Which of the following systems would be

used to solve this problem ???

Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0
Alright, since the perimeter, by definition, is 2l+2w=24 in this case, we have to have that. In addition twice the width=2*width=2w, so 2w-3=l.
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A lampshade has a height of 12cm and upper and lower diameters of 10cm and 20cm A)what area of material is required to cover tha
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(a)\ Area = 195\pi

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h = 12

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r_2 = 0.5 * d_2 = 0.5 * 20 = 10 --- upper radius

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