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3 years ago

9

The perimeter of a rectangle is 24 feet. The length is 3 feet less than twice the width. Which of the following systems would be

used to solve this problem ???

1 answer:

Ksivusya [100]3 years ago

5 0

Alright, since the perimeter, by definition, is 2l+2w=24 in this case, we have to have that. In addition twice the width=2*width=2w, so 2w-3=l.

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