Answer:
It is difficult to give a specific answer without your scenario but maybe this may help you out a bit.
Let's say you have a line like the one attached:
I labelled certain points b and u so you can use it as a reference. Now all you need to do is count all the points that lie on the same line and are found between.
In this case it would be point d and point e because the rest of the points do not line on the same line. For this problem particular scenario, the answer would be 2.
Answer:
34.87% probability that all 5 have a wireless device
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
81% of students own a wireless device.
This means that
If 5 students are selected at random, what is the probability that all 5 have a wireless device?
This is P(X = 5) when n = 5. So
34.87% probability that all 5 have a wireless device