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Kaylis [27]
3 years ago
11

the figure formed by intersection of a solid with a plane parallel to the base of the solid is congruent to the base if the soli

d is a A. frustum of a cone B. right cylinder C. Rectangular pyramid D. right cone
Mathematics
1 answer:
cricket20 [7]3 years ago
6 0

Answer:

B. Right cylinder.

Step-by-step explanation:

The figure must be congruent  ( the same size and shape) as the base. The only solid which fits this criterion is a right cylinder. The figure formed and the base will be congruent circles.

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-2*f(6-)-7*g(-7)= ???
const2013 [10]

Answer:

12f+49g

Step-by-step explanation:

-2f(-6)-7g(-7)\\12f+49g

5 0
3 years ago
Read 2 more answers
Does anyone know how to do these?
ale4655 [162]

Answer:

D.

Step-by-step explanation:

f(x) = \sqrt[3]{4x}

g(x) = 2x + 3

\frac{f}{g} (x)  = 'f' divided by 'g'

\frac{\sqrt[3]{4x} }{2x+3}    Substitute.

x cannot be -\frac{3}{2} because that would create a zero in the denominator.

That's a no-no.

It makes it 'undefined'

7 0
3 years ago
Is 15º an acute angle, right angle, obtuse<br> angle, or straight angle?<br> flant role
White raven [17]

Answer:

acute angle

Step-by-step explanation:

right is 90 degrees

obtuse is greater than 90 degrees

acuta is less than 90 degrees

straight is 180 degrees

so acute.

Brainliest appreciated

8 0
3 years ago
How many 1/2-inch cubes can fit into a larger cube with side length 2 1/2​ inches?
mote1985 [20]
The answer is (C) 125. Hope this helps!
6 0
3 years ago
Help please! show work
e-lub [12.9K]
Your answers are
A = 35.7°
B = 67.6°
C = 76.7°

cosine law

a^2 = b^2 + c^2 -2bc \cos A \\&#10;-2bc \cos A = a^2 - b^2 - c^2 \\ \\&#10;\cos A = \dfrac{a^2 - b^2 - c^2}{-2bc} \\ \\&#10;A = \cos^{-1}\left[ \dfrac{a^2 - b^2 - c^2}{-2bc} \right] \\ \\&#10;A = \cos^{-1}\left[ \dfrac{12^2 - 19^2 - 20^2}{-2(19)(20)} \right]  \\ \\&#10;A = 35.723697

A = 35.723697
sine law for the rest of the angles

\displaystyle&#10;\frac{\sin B}{b} = \frac{\sin A}{a} \\ \\&#10;\sin B = \frac{b \sin A}{a} \\ \\&#10;B = \sin^{-1} \left[ \frac{b \sin A}{a}  \right] \\ \\&#10;B = \sin^{-1} \left[ \frac{19 \sin 35.723697 }{12}  \right]  \\ \\&#10;B \approx 67.58886795

B = 67.58886795
All angles in triangle sum to 180 so find C with that

A + B + C = 180
C = 180 - A - B
C = 180 - 35.723697 - 67.58886795
C = 76.7°

7 0
3 years ago
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