the figure formed by intersection of a solid with a plane parallel to the base of the solid is congruent to the base if the soli
1 answer:
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You can re-write this quotient this way :
What's inside the square root must be greater than or equal to 0, because the domain of the square root function is defined on R+ (which is [0,+∞))
In other word we must find x so that :
at the end we get
28(x-1) ≥ 0
28x - 28 ≥ 0
28x ≥ 28
x ≥ 1
So the answer is B, x ≥ 1