Answer:
190 freshman will probably go to the party
Step-by-step explanation:
first we have to get the probability of a person going
for this we will see those who said they will go on those who asked them
38/50 = 0.76 = 76%
Now we are going to multiply the 0.76 by the 250 people, and we will obtain the probable number of freshman that come to the party
250*0.76 = 190
 
        
             
        
        
        
Answer:
52/79
Step-by-step explanation:
One costume = 156 (This is our numerator.)
All visitors = 156 + 58 + 23 = 237 (This is our denominator.)
156/237
Find the GCF to simplify (sneak peek it's 3)
156/3 = 52
237/3 = 79
52/79 (tada!)
 
        
             
        
        
        
59pounds * 5days = 295pounds
6.95pounds * 3breakfasts = 20.85pounds
12.50pounds * 1eveningmeal = 12.50pounds
295pounds + 20.85pounds + 12.50pounds = 328.35pounds
Wrote out the units just for clarity! Liz payed 328.25 pounds altogether. 
 
        
             
        
        
        
Answer:
C. 4.3 cm
Step-by-step explanation:
Since it is a right triangle you can use a²+b²=c² to solve this. Then you subtract 2 from the AC to get AD.
 
        
                    
             
        
        
        
Answer:
![A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right]](https://tex.z-dn.net/?f=A%5E%7B-1%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%26-4%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D) message SHOW_ME_THE_MONEY_
 message SHOW_ME_THE_MONEY_  
Step-by-step explanation:
The matrix
 ![A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%264%5C%5C-1%26-3%5Cend%7Barray%7D%5Cright%5D%5Crightarrow%20%7CA%7C%3D%281%20%5Ctimes%20-3%29-%28-1%5Ctimes%204%29%3D1%5C%5C%5Crightarrow%20A%5E%7B-1%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%26-4%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20%5C%5C)
We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.
Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table
Encoded message    Decoded message    message in letters by association
11	52        19	8    S	H
-8	-9         15	23  O	W
-13	-39        0	13   _	M
5	20         5	0   E	_
12	56        20	8    T	H
5	20         5	0    E	_
-2	7           13	15  M	O
9	41         14	5   N	E
25	100       25	0    Y	_
Then the message decoded is SHOW_ME_THE_MONEY_