3 years ago

Find JL if JK = 17 - x, KL = 2x - 7, and K is the midpoint of JL

1 answer:

6 0

I'm assuming that the line is JKL in order of the points from left to right.

JK + KL = JL
(17-x) + (2x-7) = JL
Simplify.
10-x = JL

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notka56 [123]

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nlexa [21]

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Step-by-step explanation:

In right triangle ABC, ∠C is a right angle, m∠A = 52° , AC = 10.01, and AB = c.

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∠C is a right angle, it means AB is hypotenuse.

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

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