Answer:
Part A:
In order to find a coterminal angle, or angles of the given angle, simply add or subtract 360 degrees of the terminal angle as many times as possible.
Part B:Simply put, coterminal angles start at 0° and end at the same place, though in different directions and multiple times around (you're probably going to want to make that sound a little more formal). Since each time around is 360°, boom
Part C: 75° is in Quadrant II, right? If I go one more time around, 75 + 360 = 435°. I can also go "backward. Starting at 0 and going clockwise, I'm going 75 fewer degrees than all the way around, so 360-75 = 285° but since I'm going "backward" 75 - 360 = -285°. One more is on you.
Step-by-step explanation:
Answer:
a. 13,17,21
b. an=a1+(n-1)4
c. no
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
Step-by-step explanation:
<h2>—Math</h2>
x² – 2x + 7 = 4x – 10
x² –2x – 4x + 7 + 10= 0
x² –6x + 17 = 0
All of these transformations are equivalent to reflection across the line y=x:
- a reflection across the y-axis followed by a clockwise rotation 90° about the origin
- a clockwise rotation 90° about the origin followed by a reflection across the x-axis
- a counter-clockwise rotation 90° about the origin followed by a reflection across the y-axis
- a reflection across the x-axis followed by a counter-clockwise rotation 90° about the origin
_____
These are all but the second choice.
... reflection across y: (x, y) ⇒ (-x, y); 90°CW: (-x, y) ⇒ (y, x)
... 90°CW: (x, y) ⇒ (y, -x); reflection across x: (y, -x) ⇒ (y, x)
... 90°CCW: (x, y) ⇒ (-y, x); reflection across y: (-y, x) ⇒ (y, x)
... reflection across x: (x, y) ⇒ (x, -y); 90°CCW: (x, -y) ⇒ (y, x)
Note that the second choice gives a different result:
... reflection across y: (x, y) ⇒ (-x, y); 90°CCW: (-x, y) ⇒ (-y, -x)
