Question

Which is the general form of the equation of the circle shown? x2 + y2 + 4x – 2y – 4 = 0 x2 + y2 + 4x – 2y + 2 = 0 x2 + y² – 4x + 2y – 4 = 0

Answer 1

Answer:

a

Step-by-step explanation:

Answer 2

The equation of a circle with center at point (h, k) and radius of r units is given by
$(x-h)^{2} +(y-k)^2=r^2$

From the diagram, the center of the given circle is at points (-2, 1) and the radius is 3 units.

Therefore, the equation of the given by
$\left(x-(-2)\right)^2+(y-1)^2=3^2 \\ \\ (x+2)^2+(y-1)^2=9 \\ \\ x^2+4x+4+y^2-2y+1=9 \\ \\ x^2+y^2+4x-2y+5-9=0 \\ \\ x^2+y^2+4x-2y-4=0$