All categories

2 years ago

The area of a particular rectangle is 72. If the length of the rectangle is twice

Mathematics

1 answer:

soldier1979 [14.2K]2 years ago

4 0

Answer:

Step-by-step explanation:

Suppose the width is "a". Then the length is 2a.

2(a²) =72 Divide both sides by 2

a²= 36

a=6

You might be interested in

Somebody help me?! Finding an angle measure given a triangle and parallel lines.

balandron [24]

Answer:

x=78

Step-by-step explanation:

the sum of all angles in a triangle=180

180-59=129

y>x

70+59=129

180-129=51

129-51=78

x=78

8 0

3 years ago

What is the domain of the function represented by the graph?

neonofarm [45]

Answer: C

Step-by-step explanation:

For a parabola, the domain is ALWAYS “all real numbers”.

Hope this helps :)

5 0

2 years ago

Read 2 more answers

A scale on a map shows that 2.52.52, point, 5 centimeters represents 151515 kilometers.

Dmitry_Shevchenko [17]

Answer:

105 km

Step-by-step explanation:

Written as a proportion, the ratio of km to cm will be the same for both distances:

(x km)/(17.5 cm) = (15 km)/(2.5 cm)

x km = (15 km)(17.5/2.5) = 105 km

105 actual kilometers are represented by 17.5 cm on the map.

5 0

2 years ago

segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc

Elan Coil [88]

Answer:

The magnetic field is $B = 3.87 *10^{-6} \ T$

Direction is inward

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The radius of BC is $r_{BC} = 30 \ cm = 0.30 \ m$

The radius of DA is $r _{DA} = 20 \ cm = 0.20 \ m$

The length of CD is $r_{CD} = 10 cm = 0.1 \ m$

The length of AB is $r_{AB} = 10 cm = 0.1 \ m$

The current is $I = 11.4A$

The magnetic field is mathematically represented as

$B = B_{BC} + B_{DA} + B_{CD} + B_{AB}$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]$

Where

$\theta_{BC} = \theta_{DA} = \frac{2\pi}{3}$

Where $\frac{2 \pi}{3} = 120^o$

$\theta_{CD} = \theta_{AB} = 0^o$

$B = \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]$

$B = 3.87 *10^{-6} \ T$

The direction is into the page

This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule the direction of current is perpendicular to the direction of magnetic field so since current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

3 0

3 years ago

What is the solution set? A.) (0, -2) B.) (2, 0) C.) (7, 0) D.) (5, 3)

max2010maxim [7]

Answer:

D.) (5, 3)

Step-by-step explanation:

Solution is where two lines intersect

Both lines intersect at x = 5 and y = 3

Answer

D.) (5, 3)

8 0

2 years ago