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attashe74 [19]
3 years ago
6

Factor 2x4 - 20x2 - 78.

Mathematics
2 answers:
Komok [63]3 years ago
8 0

Answer:

2(x² + 3)(x² - 13)

Step-by-step explanation:

2x⁴ - 20x² - 78

Factor out 2.

2(x⁴ - 10x² - 39)

Find 2 numbers that multiply to get -39 and add to get -10. Those numbers are -13 and 3.

2(x⁴ - 13x² + 3x² - 39)

2(x² + 3)(x² - 13)

Airida [17]3 years ago
7 0

Answer:

2x⁴ - 20x² - 78

To factor the expression look for the LCM of the numbers

LCM of the numbers is 2

Factorize that one out

That's

2( x⁴ - 10x² - 39)

Hope this helps

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A sector of a circle has central angle θ=5π/6 and area 15π ft2. Find the radius of this circle.
Natali [406]
5pi/6 r^2 = 15pi

R^2 = 18

R= 3sqrt(3)
6 0
3 years ago
Please help!! Giving brainliest and extra points!! (Click on photo)
MArishka [77]

Answer:

14

Step-by-step explanation:

5 0
3 years ago
I think its C, not sure
Alona [7]
Yes; you are correct.
___________________________________________________
The correct answer is:
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Answer choice:  [C]:  " x³ − 9x² + 23x <span>− 12 " .
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Note: (a </span>− b) (c − d + e) = ac − ad + ae − bc + bd − be ;
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          (x − 4) (x² <span>− 5x + 3) = 

   x * x</span>² = x³ <span>− 

   x * 5x = 5x</span>² + 

   x * 3   = 3x <span>−

   4 * x</span>²  = 4x² <span>−

   -4 * 5x =  -20x +

   -4 * 3 =  -12; 
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</span>          (x − 4) (x² − 5x + 3) = 

x³ − 5x² + 3x −4x² − (-20x) + (-12) ;

=  x³ − 5x² + 3x −4x² + 20x − 12 ;

= x³ − 5x² − 4x² + 3x + 20x − 12 ;

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Answer choice:  [C]:  " x³ − 9x²  + 23x − 12 " .
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7 0
3 years ago
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
Please answer all questions thank you.
Ad libitum [116K]
1) 78.5/pi = 25
radius = 5
The one 5 digits away from that coordinate is (2,-1)

2) This question is area, not perimeter. The width and length has to be added by 4 because of 2 feet on both sides.
9*10 = 90 - 30 = 60

3) 25pi according to pythagorean theorem.
4 0
3 years ago
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